三、地图、java实现判断点是否在多边形内

一、有些时候,地图的业务需要判断一个点的经纬度坐标是否落在多边形内

这是我找到的算法的java实现,误差在1米内,可直接使用

代码如下:

    /**
     * 判断点是否在多边形内,如果点位于多边形的顶点或边上,也算做点在多边形内,直接返回true
     * @return      点在多边形内返回true,否则返回false
     */
    public static boolean isPtInPoly(Point2D.Double point,List<Point2D.Double> pts){

        int N = pts.size();
        //如果点位于多边形的顶点或边上,也算做点在多边形内,直接返回true
        boolean boundOrVertex = true;
        //cross points count of x
        int intersectCount = 0;
        //浮点类型计算时候与0比较时候的容差
        double precision = 2e-10;
        //neighbour bound vertices
        Point2D.Double p1, p2;
        Point2D.Double p = point;

        //当前点
        p1 = pts.get(0);
        //left vertex
        for(int i = 1; i <= N; ++i){
            //check all rays
            if(p.equals(p1)){
                //p is an vertex
                return boundOrVertex;

            }

            p2 = pts.get(i % N);
            //right vertex
            if(p.x < Math.min(p1.x, p2.x) || p.x > Math.max(p1.x, p2.x)){
                //ray is outside of our interests
                p1 = p2;
                continue;//next ray left point
            }

            if(p.x > Math.min(p1.x, p2.x) && p.x < Math.max(p1.x, p2.x)){
                //ray is crossing over by the algorithm (common part of)
                if(p.y <= Math.max(p1.y, p2.y)){
                    //x is before of ray
                    if(p1.x == p2.x && p.y >= Math.min(p1.y, p2.y)){
                        //overlies on a horizontal ray
                        return boundOrVertex;
                    }

                    if(p1.y == p2.y){
                        //ray is vertical
                        if(p1.y == p.y){
                            //overlies on a vertical ray
                            return boundOrVertex;
                        }else{
                            //before ray
                            ++intersectCount;
                        }
                    }else{//cross point on the left side
                        double xinters = (p.x - p1.x) * (p2.y - p1.y) / (p2.x - p1.x) + p1.y;
                        //cross point of y
                        if(Math.abs(p.y - xinters) < precision){
                            //overlies on a ray
                            return boundOrVertex;
                        }

                        if(p.y < xinters){
                            //before ray
                            ++intersectCount;
                        }
                    }
                }
            }else{
                //special case when ray is crossing through the vertex
                if(p.x == p2.x && p.y <= p2.y){
                    //p crossing over p2
                    Point2D.Double p3 = pts.get((i+1) % N);
                    //next vertex
                    if(p.x >= Math.min(p1.x, p3.x) && p.x <= Math.max(p1.x, p3.x)){
                        //p.x lies between p1.x & p3.x
                        ++intersectCount;
                    }else{
                        intersectCount += 2;
                    }
                }
            }
            p1 = p2;
            //next ray left point
        }

        if(intersectCount % 2 == 0){
            //偶数在多边形外
            return false;
        } else {
            //奇数在多边形内
            return true;
        }
    }

 

posted on 2021-11-10 18:09  我是你爷爷的爷爷  阅读(1251)  评论(0编辑  收藏  举报

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