JS判断当前URL对当前链接高亮显示

<div class="tab-pane active" id="mainmenu">
          <ul class="nav nav-pills nav-stacked nav-quirk" id="mainul">
            <li><a href="{:U('Index/index')}"><i class="fa fa-home"></i> <span>Home</span></a></li>
            <li><a href="{:U('Mall/index')}"> <i class="fa fa-cube"></i> <span>商场管理</span></a></li>
            <li><a href="{:U('Mall/seller_list')}"> <i class="fa fa-cube"></i> <span>商户查询</span></a></li>
            <li><a href="{:U('Mall/info')}"><i class="fa fa-cube"></i> <span>我的信息</span></a></li>
            <li><a href="{:U('Index/out_login')}"><i class="fa fa-cube"></i> <span>退出系统</span></a></li>            
          </ul>
 </div>
 <script>
    //获取当前地址
    var curUrl=document.location.href;
    var myNav=document.getElementById("mainul").getElementsByTagName("a");
    for(var i=0;i<myNav.length;i++)
    {
        var links=myNav[i].getAttribute("href");
        if(curUrl.indexOf(links)!=-1)
        {
            myNav[i].parentNode.className="active";
        }
    }
 </script>