实验六
任务4
int main() { Book x[N] = {{"978-7-5327-6082-4", "门将之死", "罗纳德.伦", 42, 51}, {"978-7-308-17047-5", "自由与爱之地：入以色列记", "云也退", 49 , 30}, {"978-7-5404-9344-8", "伦敦人", "克莱格泰勒", 68, 27}, {"978-7-5447-5246-6", "软件体的生命周期", "特德姜", 35, 90}, {"978-7-5722-5475-8", "芯片简史", "汪波", 74.9, 49}, {"978-7-5133-5750-0", "主机战争", "布莱克.J.哈里斯", 128, 42}, {"978-7-2011-4617-1", "世界尽头的咖啡馆", "约翰·史崔勒基", 22.5, 44}, {"978-7-5133-5109-6", "你好外星人", "英国未来出版集团", 118, 42}, {"978-7-1155-0509-5", "无穷的开始:世界进步的本源", "戴维·多伊奇", 37.5, 55}, {"978-7-229-14156-1", "源泉", "安.兰德", 84, 59}}; printf("图书销量排名(按销售册数)：\n"); sort(x,N); output(x,N); printf("\n图书销售总额：%.2f\n",sales_amount(x,N)); return 0; } void output(Book x[],int n){ int i; for(i=0;i<n;i++) printf("%-20s %-30s %-20s %g %d\n",x[i].isbn,x[i].name,x[i].author,x[i].sales_price,x[i].sales_count); } void sort(Book x[],int n){ int i,j; Book t; for(i=0;i<n-1;i++){ for(j=0;j<n-1-i;j++){ if(x[j].sales_count<x[j+1].sales_count){ t=x[j]; x[j]=x[j+1]; x[j+1]=t; } } } } double sales_amount(Book x[],int n){ int i; double sum=0; for(i=0;i<n;i++) sum+=x[i].sales_price*x[i].sales_count; return sum; }
任务5
#include <stdio.h> typedef struct { int year; int month; int day; } Date; void input(Date *pd); int day_of_year(Date d); int compare_date(Date d1,Date d2); void test1() { Date d; int i; printf("输入日期:(以形如2024-12-16这样的形式输入)\n"); for(i=0;i<3;++i) { input(&d); printf("%d-%02d-%02d是这一年中第%d天\n\n",d.year,d.month,d.day,day_of_year(d)); } } void test2() { Date Alice_birth,Bob_birth; int i; int ans; printf("输入Alice和Bob出生日期：(以这样的形式输入)\n"); for(i=0;i<3;++i) { input(&Alice_birth); input(&Bob_birth); ans=compare_date(Alice_birth,Bob_birth); if(ans==0) printf("Alice和Bob一样大\n\n"); else if(ans==-1) printf("Alice比Bob大\n\n"); else printf("Alice比Bob小\n\n"); } } int main() { printf("测试1: 输入日期, 打印输出这是一年中第多少天\n"); test1(); printf("\n测试2: 两个人年龄大小关系\n"); test2(); } void input(Date *pd){ scanf("%d-%d-%d",&pd->year,&pd->month,&pd->day); } int day_of_year(Date d){ int i,j,run,s=0; i=d.year; if ((i %4==0&&i%100!=0)||i%400==0) run =1; else run =0; int month[12]={31,28,31,30,31,30,31,31,30,31,30,31}; if(run==1) month[1]=29; for(j=0;j<d.month-1;j++) s+=month[j]; s+=d.day; return s; } int compare_date(Date d1,Date d2){ int c; if(d1.year>d2.year){ return 1; } else if(d1.year==d2.year){ c=day_of_year(d1)-day_of_year(d2); if(c<0){ return -1; } else if(c==0){ return 0; } else{ return 1; } } else{return -1; } }
任务6
#include <stdio.h> #include <string.h> enum Role {admin, student, teacher}; typedef struct { char username[20]; char password[20]; enum Role type; } Account; void output(Account x[], int n); int main() { Account x[] = {{"A1001", "123456", student}, {"A1002", "123abcdef", student}, {"A1009", "xyz12121", student}, {"X1009", "9213071x", admin}, {"C11553", "129dfg32k", teacher}, {"X3005", "921kfmg917", student}}; int n; n = sizeof(x)/sizeof(Account); output(x, n); return 0; } void output(Account x[], int n) { enum Role s1,s2,s3,s; s1=admin; s2=student; s3=teacher; int i,j,m; for(i=0;i<n;i++){ s=x[i].type; printf("%-20s",x[i].username); m=strlen(x[i].password)-1; for(j=0;j<m;j++){ printf("*"); } for(j=m;j<20;j++){ printf(" "); } if(s==s1) printf("admin\n"); if(s==s2) printf("student\n"); if(s==s3) printf("teacher\n"); } }
任务7
#include <stdio.h> #include <string.h> typedef struct { char name[20]; char phone[12]; int vip; } Contact; void set_vip_contact(Contact x[], int n, char name[]); void output(Contact x[], int n); void display(Contact x[], int n); #define N 10 int main() { Contact list[N] = {{"刘一", "15510846604", 0}, {"陈二", "18038747351", 0}, {"张三", "18853253914", 0}, {"李四", "13230584477", 0}, {"王五", "15547571923", 0}, {"赵六", "18856659351", 0}, {"周七", "17705843215", 0}, {"孙八", "15552933732", 0}, {"吴九", "18077702405", 0}, {"郑十", "18820725036", 0}}; int vip_cnt, i; char name[20]; printf("显示原始通讯录信息: \n"); output(list, N); printf("\n输入要设置的紧急联系人个数: "); scanf("%d", &vip_cnt); printf("输入%d个紧急联系人姓名:\n", vip_cnt); for(i = 0; i < vip_cnt; ++i) { scanf("%s", name); set_vip_contact(list, N, name); } printf("\n显示通讯录列表:(按姓名字典序升序排列,紧急联系人最先显示)\n"); display(list, N); return 0; } void set_vip_contact(Contact x[], int n, char name[]) { int i; for(i=0;i<n;i++){ if(strcmp(x[i].name,name)==0) x[i].vip=1; } } void display(Contact x[], int n) { int i,j,k,cnt=0; Contact t; for(i=0;i<n-1;i++){ cnt+=1; } for(i=0;i<n-1;i++){ for(j=0;j<n-1-i;j++){ if(strcmp(x[j].name,x[j+1].name)>0){ t=x[j+1]; x[j+1]=x[j]; x[j]=t; } } } for(i=0;i<n-1;i++){ for(j=0;j<n-1-i;j++){ if((x[j].vip!=1)&&(x[j+1].vip==1)){ t=x[j+1]; x[j+1]=x[j]; x[j]=t; } } }output(x, n);printf("\n"); } void output(Contact x[], int n) { int i; for(i = 0; i < n; ++i) { printf("%-10s%-15s", x[i].name, x[i].phone); if(x[i].vip) printf("%5s", "*"); printf("\n"); } }
