leetcode Path Sum

Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.

For example:
Given the below binary tree and sum = 22,

              5
             / \
            4   8
           /   / \
          11  13  4
         /  \      \
        7    2      1

return true, as there exist a root-to-leaf path 5->4->11->2 which sum is 22.

 

/**
 * Definition for binary tree
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode(int x) { val = x; }
 * }
 */
public class Solution {
    public boolean hasPathSum(TreeNode root, int sum) {
        if(root==null){
            return false;
        }
        int differ=sum-root.val;
        if(root.left==null&&root.right==null&&differ==0){
            return true;
        }
        return hasPathSum(root.left,differ)||hasPathSum(root.right,differ);
    }
}

 

posted @ 2014-10-28 06:20  lilyfindjob  阅读(103)  评论(0编辑  收藏  举报