Leetcode 237 Delete Node in a Linked List

Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.

Supposed the linked list is 1 -> 2 -> 3 -> 4 and you are given the third node with value 3, the linked list should become 1 -> 2 -> 4 after calling your function.

将这个node的值改为下一个node的,并且删除下一个node即可。

class Solution:
    # @param {ListNode} node
    # @return {void} Do not return anything, modify node in-place instead.
    def deleteNode(self, node):
        node.val = node.next.val
        node.next = node.next.next

 

posted @ 2015-07-15 12:35  lilixu  阅读(229)  评论(0编辑  收藏  举报