摘要： 1 private void EM_Init (Instances inst) 2 throws Exception { 3 int i, j, k; 4 5 // 由于EM算法对初始值较敏感，故选择run k means 10 times and choose best solution 6 SimpleKMeans bestK = null; 7 double bestSqE = Double.MAX_VALUE; 8 for (i = 0; i < 10; i++) { 9 SimpleKMeans sk = new Si... 阅读全文