字符串转数字 简单代码实现
代码如下:
#include <stdio.h> #define u8 unsigned char static const int MAC_LENGTH = 6; static u8 char1Tonum(u8 ch) { if((ch>='0')&&(ch<='9')) return ch - '0'; else if ((ch>='a')&&(ch<='f')) return ch - 'a' + 10; else if ((ch>='A')&&(ch<='F')) return ch - 'A' + 10; else return 0xff; } //简单的把字符串转为数字 (比如把MAC地址转为6个数字) static u8 char2Tonum(u8 hch, u8 lch) { return ((char1Tonum(hch) << 4) | char1Tonum(lch)); } static void charToArray(u8* array,u8* stringBuf) { for(int i =0,j=0;i<MAC_LENGTH;i++,j+=2) { array[i] = char2Tonum(stringBuf[j],stringBuf[j+1]); printf("0x%x\n",array[i]); } } int main() { u8 buf[MAC_LENGTH] = {0}; u8 bufMac[MAC_LENGTH*2+1] = "112233445566"; charToArray(buf,bufMac); /* for(int i =0,j=0;i<MAC_LENGTH;i++,j+=2) { buf[i] = char2Tonum(bufMac[j],bufMac[j+1]); printf("0x%x\n",buf[i]); } */ return 0; }
posted on 2013-10-23 14:32 Cynthia&Sky 阅读(772) 评论(0) 编辑 收藏 举报