07 2021 档案
list.stream()
摘要:1、list分组: Map<String,List<AlarmStatisticalDO>> map = alarmStatisticalDOList.stream().collect(Collectors.groupingBy(a -> a.getAlarmDate())); for (Strin 阅读全文
posted @ 2021-07-20 12:03 LJD泊水 阅读(271) 评论(0) 推荐(0)