[LeetCode] 330. Patching Array 数组补丁

Given a sorted positive integer array nums and an integer n, add/patch elements to the array such that any number in range [1, n] inclusive can be formed by the sum of some elements in the array. Return the minimum number of patches required.

Example 1:
nums = [1, 3]n = 6
Return 1.

Combinations of nums are [1], [3], [1,3], which form possible sums of: 1, 3, 4.
Now if we add/patch 2 to nums, the combinations are: [1], [2], [3], [1,3], [2,3], [1,2,3].
Possible sums are 1, 2, 3, 4, 5, 6, which now covers the range [1, 6].
So we only need 1 patch.

Example 2:
nums = [1, 5, 10]n = 20
Return 2.
The two patches can be [2, 4].

Example 3:
nums = [1, 2, 2]n = 5
Return 0.

Credits:
Special thanks to @dietpepsi for adding this problem and creating all test cases.

Java:

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
public int minPatches(int[] nums, int n) {
    long miss = 1;
    int count = 0;
    int i = 0;
  
    while(miss <= n){
        if(i<nums.length && nums[i] <= miss){
            miss = miss + nums[i];
            i++;
        }else{
            miss += miss;
            count++;
        }
    }
  
    return count;
} 

Python:

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
class Solution(object):
    def minPatches(self, nums, n):
        """
        :type nums: List[int]
        :type n: int
        :rtype: int
        """
        patch, miss, i = 0, 1, 0
        while miss <= n:
            if i < len(nums) and nums[i] <= miss:
                miss += nums[i]
                i += 1
            else:
                miss += miss
                patch += 1
 
        return patch  

C++:

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
class Solution {
public:
    int minPatches(vector<int>& nums, int n) {
        long miss = 1, res = 0, i = 0;
        while (miss <= n) {
            if (i < nums.size() && nums[i] <= miss) {
                miss += nums[i++];
            } else {
                miss += miss;
                ++res;
            }
        }
        return res;
    }
};

C++:

1
2
3
4
5
6
7
8
9
10
11
12
13
class Solution {
public:
    int minPatches(vector<int>& nums, int n) {
        long miss = 1, k = nums.size(), i = 0;
        while (miss <= n) {
            if (i >= nums.size() || nums[i] > miss) {
                nums.insert(nums.begin() + i, miss);
            }
            miss += nums[i++];
        }
        return nums.size() - k;
    }
};

  

 

All LeetCode Questions List 题目汇总

posted @   轻风舞动  阅读(453)  评论(0编辑  收藏  举报
编辑推荐:
· 智能桌面机器人:用.NET IoT库控制舵机并多方法播放表情
· Linux glibc自带哈希表的用例及性能测试
· 深入理解 Mybatis 分库分表执行原理
· 如何打造一个高并发系统?
· .NET Core GC压缩(compact_phase)底层原理浅谈
阅读排行:
· 手把手教你在本地部署DeepSeek R1,搭建web-ui ,建议收藏!
· 新年开篇:在本地部署DeepSeek大模型实现联网增强的AI应用
· Janus Pro:DeepSeek 开源革新,多模态 AI 的未来
· 互联网不景气了那就玩玩嵌入式吧,用纯.NET开发并制作一个智能桌面机器人(三):用.NET IoT库
· 【非技术】说说2024年我都干了些啥
点击右上角即可分享
微信分享提示