[LeetCode] 248. Strobogrammatic Number III 对称数III
A strobogrammatic number is a number that looks the same when rotated 180 degrees (looked at upside down).
Write a function to count the total strobogrammatic numbers that exist in the range of low <= num <= high.
For example,
Given low = "50", high = "100", return 3. Because 69, 88, and 96 are three strobogrammatic numbers.
Note:
Because the range might be a large number, the low and high numbers are represented as string.
246. Strobogrammatic Number和247. Strobogrammatic Number II的拓展,求一个区间的数里有多少个对称数。有了247一题作基础,这里我们可以先用迭代方法求出所有长度满足的数,再通过与low,high的compare比较,选出最终的结果并count。
Java:
public class Solution { public List<String> helper(int n, int max) { if (n == 0) return new ArrayList<String>(Arrays.asList("")); if (n == 1) return new ArrayList<String>(Arrays.asList("1", "8", "0")); List<String> list = helper(n - 2, max); List<String> result = new ArrayList<String>(); for (int i = 0; i < list.size(); i++) { String s = list.get(i); if (n != max) result.add("0" + s + "0"); result.add("1" + s + "1"); result.add("8" + s + "8"); result.add("6" + s + "9"); result.add("9" + s + "6"); } return result; } public int strobogrammaticInRange(String low, String high) { int count = 0; List<String> result = new ArrayList<String>(); for (int i = low.length(); i <= high.length(); i++) { result.addAll(helper(i, i)); } for (String str : result) { if (str.length() == low.length() && str.compareTo(low) < 0 || str.length() == high.length() && str.compareTo(high) > 0) continue; count++; } return count; } }
Java:
public class Solution { private int count = 0; private Map<Character, Character> map = new HashMap<>(); public int strobogrammaticInRange(String low, String high) { if (low == null || low.length() == 0 || high == null || high.length() == 0) { return 0; } fillMap(); for (int n = low.length(); n <= high.length(); n++) { char[] arr = new char[n]; getStrobogrammaticNumbers(arr, 0, n - 1, low, high); } return count; } private void getStrobogrammaticNumbers(char[] arr, int start, int end, String low, String high) { if (start > end) { String s = new String(arr); if ((s.length() == 1 || s.charAt(0) != '0') && compare(low, s) && compare(s, high)) { count++; } return; } for (char c : map.keySet()) { arr[start] = c; arr[end] = map.get(c); if ((start < end) || (start == end && map.get(c) == c)) { getStrobogrammaticNumbers(arr, start + 1, end - 1, low, high); } } } // Return true if s1 <= s2 private boolean compare(String s1, String s2) { if (s1.length() == s2.length()) { if (s1.compareTo(s2) <= 0) { return true; } else { return false; } } return true; } private void fillMap() { map.put('0', '0'); map.put('1', '1'); map.put('8', '8'); map.put('6', '9'); map.put('9', '6'); } }
类似题目:
[LeetCode] 246. Strobogrammatic Number 对称数
[LeetCode] 247. Strobogrammatic Number II 对称数II
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