2020年9月23日LC打卡

 

 递归算法easy题

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    TreeNode* mergeTrees(TreeNode* t1, TreeNode* t2) {
        if(t1 == NULL) {
            return t2;
        }
        if(t2 == NULL) {}
            return t1;
        }
        auto ans = new TreeNode(t1->val + t2->val);
        ans->left = mergeTrees(t1->left, t2->left);
        ans->right = mergeTrees(t1->right, t2->right);
        return ans;
    }
};

  

posted @ 2020-09-23 08:24  LightAc  阅读(121)  评论(0编辑  收藏  举报
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