A1064. Complete Binary Search Tree (30)

A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties:

  • The left subtree of a node contains only nodes with keys less than the node's key.
  • The right subtree of a node contains only nodes with keys greater than or equal to the node's key.
  • Both the left and right subtrees must also be binary search trees.

A Complete Binary Tree (CBT) is a tree that is completely filled, with the possible exception of the bottom level, which is filled from left to right.

Now given a sequence of distinct non-negative integer keys, a unique BST can be constructed if it is required that the tree must also be a CBT. You are supposed to output the level order traversal sequence of this BST.

Input Specification:

Each input file contains one test case. For each case, the first line contains a positive integer N (<=1000). Then N distinct non-negative integer keys are given in the next line. All the numbers in a line are separated by a space and are no greater than 2000.

Output Specification:

For each test case, print in one line the level order traversal sequence of the corresponding complete binary search tree. All the numbers in a line must be separated by a space, and there must be no extra space at the end of the line.

Sample Input:

10
1 2 3 4 5 6 7 8 9 0

Sample Output:

6 3 8 1 5 7 9 0 2 4
 1 #include <stdio.h>
 2 #include <stdlib.h>
 3 #include <iostream>
 4 #include <string.h>
 5 #include <math.h>
 6 #include <algorithm>
 7 #include <string>
 8 #include <stack> 
 9 #include <queue>
10 using namespace std;
11 const int maxn=1010; 
12 int n,number[maxn],CBT[maxn];
13 int shuzucount=0;
14 
15 void inOrder(int root)//这里中序遍历的目的是,
16 {//将中序的结果数组num与过程结合,得到CBT 
17    if(root>n)return;
18    inOrder(root*2);
19    CBT[root]=number[shuzucount++];
20    inOrder(root*2+1);    
21 }
22 int main(){
23    scanf("%d",&n);
24    for(int i=0;i<n;i++)
25    {
26        scanf("%d",&number[i]);
27    }
28    sort(number,number+n);
29    inOrder(1);
30       for(int i=1;i<=n;i++)
31       {
32           printf("%d",CBT[i]);
33           if(i<n)printf(" ");
34        } 
35     return 0;
36 }

 

posted @ 2015-03-08 23:47  Joilee  阅读(185)  评论(0编辑  收藏  举报