MySQL SQL 处理 JSON 数据

目录

• 源数据
• case 1
• case 2
• case 3

源数据#

[{"attrId":2762280,"attrValueId":3475578},{"attrId":2762279,"attrValueId":3475579}]

目的：提取出 json 中的 attrValueId

case 1#

select 
JSON_EXTRACT(t.`saleAttrValues`, '$[*].attrValueId') as tt
from `sp_unifiedsku` t
where t.`unifiedProductId` = 252329
and t.status = 0
group by tt

case 2#

group by 用来去重

这里的$[0]指的是取 case 1 的第一个元素

select 
JSON_EXTRACT(JSON_EXTRACT(t.`saleAttrValues`, '$[*].attrValueId'), '$[0]') as tt
from `sp_unifiedsku` t
where t.`unifiedProductId` = 252329
and t.status = 0
group by tt

case 3#

将id拼接起来

select GROUP_CONCAT(tt) from (select 
JSON_EXTRACT(JSON_EXTRACT(t.`saleAttrValues`, '$[*].attrValueId'), '$[0]') as tt
from `sp_unifiedsku` t
where t.`unifiedProductId` = 252329
and t.status = 0
group by tt) as ttt