Hashtable的测试

import java.util.Enumeration;
import java.util.Hashtable;

class TT {
    private String name = null; //name和age是作为键的
    private Integer age = 0;
    
    public TT(String name,int age) { //构造函数没有返回值
        this.name = name;
        this.age = age;
    }
/*
 * 要用对象作为键，就要重载equals和hashcode这两个方法，目的是使用get方法
 */
    @Override
    public boolean equals(Object obj) {
        // TODO Auto-generated method stub
        if((obj != null) && (obj instanceof TT)) {
            TT objTemp = (TT)obj;
            if((name.equals(objTemp.name)) && (age.equals(objTemp.age))) {
                return true;
            }else {
                return false;
            }
        }else {
            return false;
        }
        
    }
    //这是get方法比较的重要依据，呵呵
    @Override
    public int hashCode() { 
        // TODO Auto-generated method stub
        return name.hashCode() + age;
    }
    
    public String toString() {
        return name + "--" + age;
    }
        
}
public class HashTable {
    public static void main(String[] args) {
        Hashtable<TT,Integer> ht = new Hashtable<TT,Integer>();
        ht.put(new TT("张三",20),new Integer(1));
        ht.put(new TT("李四",18),new Integer(2));
        ht.put(new TT("王麻子",12),new Integer(3));
        
        System.out.println("取值"+ ht.get(new TT("李四",20)));
        Enumeration<TT> keys = ht.keys();
        while(keys.hasMoreElements()) {
            TT tt = (TT)keys.nextElement();
            System.out.println(tt);
            System.out.println(ht.get(tt));
        }
        System.out.println(ht.get(new TT("李四",18)));
    }
}