mvc post list到后台
2020-07-27 11:59 若藜520 阅读(238) 评论(0) 编辑 收藏 举报@model IEnumerable<mvctest.Models.SysUser> @{ ViewBag.Title = "Index"; } <h2>Index</h2> @using (Html.BeginForm()) { <p> @Html.ActionLink("Create New", "Create") </p> <table class="table"> <tr> <th> @Html.DisplayNameFor(n => n.UserName) </th> <th> @Html.DisplayNameFor(model => model.Email) </th> <th> @Html.DisplayNameFor(model => model.Password) </th> <th> @Html.DisplayNameFor(model => model.Phone) </th> <th></th> </tr> @{ var list = Model.ToList(); for (int i = 0; i < list.Count; i++) { <tr> <td> @Html.EditorFor(modelItem => list[i].UserName, new { htmlAttributes = new { @class = "form-control" } }) </td> <td> @Html.EditorFor(modelItem => list[i].Email, new { htmlAttributes = new { @class = "form-control" } }) </td> <td> @Html.EditorFor(modelItem => list[i].Password, new { htmlAttributes = new { @class = "form-control" } }) </td> <td> @Html.EditorFor(modelItem => list[i].Phone, new { htmlAttributes = new { @class = "form-control" } }) </td> <td> @Html.ActionLink("Edit", "Edit", new { id = list[i].ID }) | @Html.ActionLink("Details", "Details", new { id = list[i].ID }) | @Html.ActionLink("Delete", "Delete", new { id = list[i].ID }) </td> </tr> } } </table> <input type="submit" value="提交" /> }
[HttpPost] public ActionResult Index(List<mvctest.Models.SysUser> list) { return View(db.SysUsers.ToList()); }
注意Action参数名称与view中的list名称一致才可以,这里view中Name属性使用了list[0].username这样的名称,即view中list的名称为list,所以Action参数也要命名为list