lintcode-480-二叉树的所有路径
480-二叉树的所有路径
给一棵二叉树,找出从根节点到叶子节点的所有路径。
您在真实的面试中是否遇到过这个题? Yes
样例
给出下面这棵二叉树:
所有根到叶子的路径为:
[
"1->2->5",
"1->3"
]标签
二叉树 谷歌 二叉树遍历 脸书
思路
使用深度优先搜索 + 回溯
code
/**
* Definition of TreeNode:
* class TreeNode {
* public:
* int val;
* TreeNode *left, *right;
* TreeNode(int val) {
* this->val = val;
* this->left = this->right = NULL;
* }
* }
*/
class Solution {
public:
/**
* @param root the root of the binary tree
* @return all root-to-leaf paths
*/
vector<string> binaryTreePaths(TreeNode* root) {
// Write your code here
if (root == NULL) {
return vector<string>();
}
vector<string> result;
vector<int> path;
DFS(root, path, result);
return result;
}
void DFS(TreeNode * root, vector<int> &path, vector<string> &result) {
path.push_back(root->val);
if (root->left == NULL && root->right == NULL) {
string temp;
for (int p : path) {
char pa[256];
sprintf(pa, "%d", p);
temp += pa;
temp += "->";
}
result.push_back(temp.substr(0, temp.size()-2));
return;
}
if (root->left != NULL) {
DFS(root->left, path, result);
path.pop_back();
}
if (root->right != NULL) {
DFS(root->right, path, result);
path.pop_back();
}
}
};