UVa 11044 - Searching for Nessy
The Loch Ness Monsteris a mysterious and unidentified animal said to inhabit Loch Ness, a large deep freshwater loch near the city of Inverness in northern Scotland. Nessie is usually categorized as a type of lake monster. http://en.wikipedia.org/wiki/Loch_Ness_Monster
In July 2003, the BBC reported an extensive investigation of Loch Ness by a BBC team, using 600 separate sonar beams, found no trace of any ¨sea monster¨ (i.e., any large animal, known or unknown) in the loch. The BBC team concluded that Nessie does not exist. Now we want to repeat the experiment.
Given a grid of n rows and m columns representing the loch, 6n, m
10000, find the minimum number s of sonar beams you must put in the square such that we can control every position in the grid, with the following conditions:
- one sonar occupies one position in the grid; the sonar beam controls its own cell and the contiguous cells;
- the border cells do not need to be controlled, because Nessy cannot hide there (she is too big).
For example,

where X represents a sonar, and the shaded cells are controlled by their sonar beams; the last figure gives us a solution.
Input
The first line of the input contains an integer, t, indicating the number of test cases. For each test case, there is a line with two numbers separated by blanks, 6n, m
10000, that is, the size of the grid (nrows and m columns).
Output
For each test case, the output should consist of one line showing the minimum number of sonars that verifies the conditions above.
Sample Input
3 6 6 7 7 9 13
Sample Output
4 4 12
#include<stdio.h> #include<math.h> int main() { int T, n, m; scanf("%d", &T); while(T--) { scanf("%d%d", &n, &m); if((n-2)%3 != 0) n = (n-2)/3 + 1; else n = (n-2)/3; if((m-2)%3 != 0) m = (m-2)/3 + 1; else m = (m-2)/3; printf("%d\n", n*m); } return 0; }
解题思路:
怪不得通过率那么高,求格中九宫格的最小数量,而且注意题目说了边上的格子是可以不算的,所以可以减去2在进行整除3,当然,如果除不尽当然还是再加上一个九宫格

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