摘要: // 求2点之间的距离 deg (p1 , p2){ var x = p1[0] - p2[0]; var y = p1[1] - p2[1]; var deg = Math.atan(Math.abs(x / y)) * 180 / Math.PI if( x > 0 ){ if( y > 0 ) 阅读全文
posted @ 2020-11-23 14:35 blurs 阅读(178) 评论(0) 推荐(0) 编辑
摘要: ArcGIS底图服务地址 http://server.arcgisonline.com/arcgis/rest/services http://cache1.arcgisonline.cn/arcgis/rest/services 阅读全文
posted @ 2020-11-23 09:30 blurs 阅读(689) 评论(0) 推荐(0) 编辑