九度OJ 1136:Number Steps(步数) (基础题)
- 题目描述:
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Starting from point (0,0) on a plane, we have written all non-negative integers 0,1,2, ... as shown in the figure. For example, 1, 2, and 3 has been written at points (1,1), (2,0), and (3, 1) respectively and this pattern has continued.
You are to write a program that reads the coordinates of a point (x, y), and writes the number (if any) that has been written at that point. (x, y) coordinates in the input are in the range 0...5000.
- 输入:
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The first line of the input is N, the number of test cases for this problem. In each of the N following lines, there is x, and y representing the coordinates (x, y) of a point.
- 输出:
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For each point in the input, write the number written at that point or write No Number if there is none.
- 样例输入:
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3 4 2 6 6 3 4
- 样例输出:
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6 12 No Number
思路:
细节题,要分清各类情况。
代码:
#include <stdio.h> int main(void) { int n, i; int x, y; while (scanf("%d", &n) != EOF) { for(i=0; i<n; i++) { scanf("%d%d", &x, &y); if (x == y || x-y == 2) { if (x%2 == 0) printf("%d\n", x+y); else printf("%d\n", x+y-1); } else printf("No Number\n"); } } return 0; } /************************************************************** Problem: 1136 User: liangrx06 Language: C Result: Accepted Time:20 ms Memory:912 kb ****************************************************************/