c语言寒假大作战04

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|:---|:---😐
|这个作业属于那个课程|https://edu.cnblogs.com/campus/zswxy/CST2019-2/|
|这个作业要求在哪里|https://edu.cnblogs.com/campus/zswxy/CST2019-2/homework/10246|
|这个作业的目标|给计算写出结果|
|作业正文|https://i-beta.cnblogs.com/posts/edit;postId=12251658|
|参考文献|学长视频 百度|

1.作业头

2.设计思路和遇到的问题

1.分析语法
2.打出代码
问题.语法不够熟练,需百度查资料,并且多次尝试。

3.程序结果截图

4.程序代码

include<stdio.h>

include<stdlib.h>

void operation1();
void operation2();
void operation3();
void menu();
void help();
void error();
int main()
{
int Grade=1;
printf("口算生成器\n欢迎使用口算生成器:)\n\n");
help();
menu();
while(Grade!=5){
scanf("%d",&Grade);
printf("<执行操作:)\n\n");
switch(Grade){
case 1:operation1();break;
case 2:operation2();break;
case 3:operation3();break;
case 4:help();break;
case 5:printf("程序结束,欢迎下次使用 任意键结束......\n");break;
default:error();break;
}if(Grade!=5) menu();
}
return 0;
}
void operation1(){
int a,b,i;
printf("现在是一年级题目:\n请输入生成个数>");
scanf("%d",&a);
for(i=0;i<a;i++){
int yi=rand()%11;
int er=rand()%11;
char c[2]={'+','-'};
b=rand()%2;
if(c[b]'+'){
printf("%2d %c %2d= %d\n",yi,c[b],er,yi+er);
}
else{
printf("%2d %c %2d= %d\n",yi,c[b],er,yi-er);
}
}
}
void operation2(){
int a,b,i;
printf("现在是二年级题目:\n请输入生成个数>");
scanf("%d",&a);
for(i=0;i<a;i++){
double yi=rand()%101;
double er=rand()%101;
double san=rand()%100+1;
char c[2]={'*','/'};
b=rand()%2;
if(c[b]
'/')printf("%2g / %2g= %g\n",yi,san,yi/san);
else printf("%2g * %2g= %g\n",yi,er,yier);
}
}
void operation3(){
int a,b,i,b1;
printf("现在是三年级题目:\n请输入生成个数>");
scanf("%d",&a);
for(i=0;i<a;i++){
double yi=rand()%101;
double er=rand()%101;
double san=rand()%101;
double si=rand()%100+1;
char c[4]={'+','-','
','/'};
b=rand()%4;
b1=rand()%4;
if(c[b]''){
switch(c[b1]){
case '-':
printf("%2g %c %2g %c %2g= %g\n",yi,c[b],er,c[b1],san,yi
er-san);break;
case '+':
printf("%2g %c %2g %c %2g= %g\n",yi,c[b],er,c[b1],san,yier+san);break;
case '/':
printf("%2g %c %2g %c %2g= %g\n",yi,c[b],er,c[b1],si,yi
er/si);break;
case '':
printf("%2g %c %2g %c %2g= %g\n",yi,c[b],er,c[b1],san,yi
er*san);break;
}
}
if(c[b]
'+'){
switch(c[b1]){
case '-':
printf("%2g %c %2g %c %2g= %g\n",yi,c[b],er,c[b1],san,yi+er-san);break;
case '+':
printf("%2g %c %2g %c %2g= %g\n",yi,c[b],er,c[b1],san,yi+er+san);break;
case '/':
printf("%2g %c %2g %c %2g= %g\n",yi,c[b],er,c[b1],si,yi+er/si);break;
case '':
printf("%2g %c %2g %c %2g= %g\n",yi,c[b],er,c[b1],san,yi+er
san);break;
}
}
if(c[b]'-'){
switch(c[b1]){
case '-':
printf("%2g %c %2g %c %2g= %g\n",yi,c[b],er,c[b1],san,yi-er-san);break;
case '+':
printf("%2g %c %2g %c %2g= %g\n",yi,c[b],er,c[b1],san,yi-er+san);break;
case '/':
printf("%2g %c %2g %c %2g= %g\n",yi,c[b],er,c[b1],si,yi-er/si);break;
case '':
printf("%2g %c %2g %c %2g= %g\n",yi,c[b],er,c[b1],san,yi-er
san);break;
}
}
if(c[b]
'/'){
switch(c[b1]){
case '-':
printf("%2g %c %2g %c %2g= %g\n",yi,c[b],si,c[b1],san,yi/si-san);break;
case '+':
printf("%2g %c %2g %c %2g= %g\n",yi,c[b],si,c[b1],san,yi/si+san);break;
case '/':
printf("%2g %c %2g %c %2g= %g\n",yi,c[b],si,c[b1],si,yi/si/si);break;
case '':
printf("%2g %c %2g %c %2g= %g\n",yi,c[b],si,c[b1],san,yi/si
san);break;
}
}
}
}
void menu(){
printf("操作列表:\n1)一年级 2)二年级 3)三年级\n4)帮助 5)退出程序\n请输入操作>");
}
void help(){
printf("帮助信息:\n您需要输入命令代号来进行操作,且\n一年级题目为不超过十位的加减法;\n二年级题目为不超过百位的乘除法;\n三年级题目为不超过百位的加减乘除混合题目.\n\n");
}
void error(){
printf("Error!!!\n错误操作指令,请重新输入\n\n");
}

5. Gitee上传截图与链接

6.git链接

https://gitee.com/luohui456/luohui20199243/tree/master/

posted @ 2020-02-17 10:51  驱逐003  阅读(119)  评论(0编辑  收藏  举报