dom4j如何解析xml

简单解析自己定义的xml文件，首先，给解析xml文件的类来个构造方法：

public xmlData(File xmlFile)  {
        file = xmlFile;
        try {
            saxReader = new SAXReader();
            saxReader.setEncoding("UTF-8");
            doc = saxReader.read(this.file);
            
            init();
        } catch (DocumentException e) {
            throw new Exception("Open xml file " + xmlFile.getAbsolutePath()
                + " failed with error:" + e.getMessage());        }
    }

下面是初始化数据的方法：

private void init() throws Exception {
        try {
            Node node = doc.selectSingleNode("//Com/User");
            user = node.valueOf("@User");
            name = node.valueOf("@Name");
           }catch(Exception e){
               throw new Exception("init xml file fail"+e.getMessage());
           }

   }