作业

一：复习巩固题

1、以下格式自行推导至少10遍

def index(x, y):

print(x, y)

def wrapper(*args, **kwargs): # args=(1,2) kwargs=

index(*args, **kwargs) # index(1,2,a=1,b=2)

# index(*(1,2),**{"a":1,"b":2}) # index(1,2,a=1,b=2)

wrapper(1, 2, a=1, b=2)

def index(x,y):

print(x,y)

def wrapper(*args,**kwargs):#args=(1,2) kwargs=

index(*args,**kwargs)#index(1,2,a=1,b=2)

# index(*(1,2),**{"a":1,"b":2}) # index(1,2,a=1,b=2)

wrapper(1,2,a=1,b=2)

def index(x,y):

print(x,y)

def wrapper(*args,**kwargs):#args=(1,5) kwargs

index(*args,**kwargs)#index(1,5,z=1,r=3,t=4)

#index(*(1,5),**{1,5,z=1,r=3,t=4})

wrapper(1,5,z=1,r=3,t=4)

2、练习把参数包给函数10遍

步骤一：准备好一个函数，该函数体代码需要一个参数

def func():

print(x)

def func():

print(x)

def func():

print(x)

def func():

print(x)

def func():

print(x)

def func():

print(x)

def func():

print(x)

def func():

print(x)

def func():

print(x)

def fun():

print(x)

def func():

print(x)

步骤二：包值

x = 2

def func():

print(x)

x = 2

def func():

print(x)

x = 2

def func():

print(x)

x = 2

def func():

print(x)

x = 2

def func():

print(x)

x = 2

def func():

print(x)

x=2

def func():

print(x)

x = 2

def func():

print(x)

x=2

def func():

print(x)

x=2

def fun():

print(x)

x=2

def func():

print(x)

步骤三：闭到outter函数内

def outter():

x = 2

def func():

print(x)

def outter():

x=2

def func():

print(x)

def outter():

x=2

def func():

print(x)

def outter():

x=2

def func():

print(x)

def outter():

x=2

def func():

print(x)

def outter():

x=2

def func():

print(x)

def outter():

x=2

def func():

print(x)

def outter():

x=2

def func():

print(x)

def outter():

x=2

def func():

print(x)

def outter():

x=2

def func():

print(x)

步骤四：基于return将内部func返回到全局

def outter():

x = 2

def func():

print(x)

return func # 一定不要加括号

f = outter()

def outter():

x=2

def func():

print(x)

return func

f=outter()

def outter():

x=2

def func():

print(x)

return func

f=outter()

def outter():

x=2

def func():

print(x)

return func

f=outter()

def outter():

x=2

def func():

print(x)

return func

f=outter()

def outter():

x=2

def func():

print(x)

return func

f=outter()

def outter():

x=2

def func():

print(x)

return func

f = outter()

def outter():

x=2

def func():

print(x)

return func

f = outter()

def outter():

x=2

def func():

print(x)

return func

f=outter()

def outter():

x=2

def func():

print(x)

return func

f=outter()

0步骤五：最终格式，把outter写活

def outter(x):

# x = 2 # 注释掉

def func():

print(x)

return func

f1 = outer(1) # 把x=1包给函数func

f2 = outer(2) # 把x=2包给函数func

f3 = outer(3) # 把x=3包给函数func

def outter(x):

# x=2

def func():

print(x)

return func

f1 = outter(1)

f2 = outter(2)

f3 = outter(3)

def outter(x):

# x=2

def func():

print(x)

return func

f1 = outter(1)

f2=outter(2)

f3=outter(3)

def outter(x):

#x=2

def func():

print(x)

return func

f1 = outter(1)

f2 = outter(2)

f3 = outter(3)

def outter(x):

#x=2

def func():

print(x)

return func

f1 = outter(1)

f2 = outter(2)

f3=outter(3)

def outter(x):

# x=2

def func():

print(x)

return func

f1=outter(1)

f2=outter(2)

f3=outter(3)

def outter(x):

# x=2

def func():

print(x)

return func

f1 = outter(1)

f2 = outter(2)

f3 = outter(3)

def outter(x):

# x=2

def func():

print(x)

return func

f1 = outter(1)

f2 = outter(2)

f3 = outter(3)

def outter(x):

# x=2

def func():

print(x)

return func

f1 = outter(1)

f2 = outter(2)

f3 = outter(3)

def outter(x):

#x=2

def func():

print(x)

return func

f1 = outter(1)

f2 = outter(2)

f3 = outter(3)

def outter(x):

# x=2

def func():

print(x)

return func

f1 = outter(1)

f2 = outter(2)

f3 = outter(3)

二：作业要求：下述所有代码画出名称空间嵌套图以及分析代码执行流程

1、以定义阶段为准，先画出名称空间的嵌套关系图

2、然后找到调用函数的位置，写出函数调用时代码的执行过程，涉及到名字的查找时，参照1中画好

的嵌套图，标明查找顺序，一层一层直到找到位置

=题目一=

input = 333

def func():

input = 444

print(input)

func()

print(input)

名称空间的嵌套关系:

input=333是在全局空间

input=444是在func函数的局部空间

第一个print(input)在局部空间找到了

第二个print(input)在全局空间找到的

=题目二=

def func():

print(x)

x = 111

func()

x=111在全局空间

func()在局部空间

print(x)在局部空间，局部空间找不到，在全局空间找到的，

# =题目三=

x = 1

def func():

print(x)

def foo():

x = 222

func()

foo()

x=1在全局空间

print(x)在局部空间没找到变量，在全局空间找到。

foo()函数内调用func函数，所以打印1

# =题目四=

input = 111

def f1():

def f2():

# input=333

print(input)

input = 222

f2()

f1()

input=111在全局变量

input=222在局部空间

f2函数在自己的没找到变量在f1函数局部空间找到了input=222，f1调用f2，所以答应了222

# =题目五=

x = 111

def func():

print(x)

x = 222

func()

func函数报错，x变量在打印之后

注释x=222就不会报错了，然后再全局变量中找到x=111

# =题目六=

x = 111

def foo():

print(x, )

def bar():

print(x)

foo()

bar()

foo函数局部内没有变量，从全局变量中找到x=111

bar函数局部内没有变量，从全局变量中找到x=1111

# =题目七=

x = 1

def func2():

func1()

x = 2

def func1():

print(x)

x = 3

func2()

func2函数调用func1函数

func1函数局部空间内没有变量，向外找，找到x=3，所以打印3.注意：惯性思维向上找是错误的

# =题目八=

1、如下全局变量记录了当前登录用户，编写登录功能，一旦用户登录成功，则将全局变量赋值为当前登录的用户名

login_user = None

2、针对之前编写的查询余额的功能，添加额外的逻辑：如果用户没有登录，则先执行登录功能

def login():

user = input('请输入用户名:').strip()

pwd = input('请输入用户名:').strip()

if user == 'liu' and pwd == '123':

# 若用户登录成功，给user_info赋值，证明用户已登录

global user_info # 函数内部可以修改外部的不可变类型的变量

user_info = user

print('login success!')

else:

print('login error!')

login()

def check_money(user):

if user_info:

db_path = 'a.txt'

with open(db_path, 'rt', encoding='utf-8') as f:

# 1）将db_path文件数据一行一行读取出来,将所有用户添加到列表

for lines in f:

# 2)判断如果user 在 在当前这行数据中，证明找到该用用户

if user in lines:

user, pwd, money = lines.strip().split('😂

print(money)

else:

print('用户没登录，请先登录!')

login()

check_money('liu')