DQL 语言 --分页查询 11

一、应用场景

  当要显示的数据,一页显示不全,需要分页提交sql请求

二、语法

 select 查询列表
 from 表
 【join type join 表2
 on 连接条件
 where 筛选条件
 group by 分组字段
 having 分组后的筛选
 order by 排序的字段】
 limit 【offset,】size;

注意:

   offset要显示条目的起始索引(起始索引从0开始)
   size 要显示的条目个数

三、特点

   ①limit语句放在查询语句的最后
   ②公式
     要显示的页数 page,每页的条目数size

 select 查询列表
 from 表
 limit (page-1)*size,size;

 size=10

 page 
 1     0
 2      10
 3      20

 

#案例1:查询前五条员工信息

SELECT * FROM  employees LIMIT 0,5;  #-------方式1

SELECT * FROM  employees LIMIT 5;    #-------方式2

 

#案例2:查询第11条——第25条

SELECT * FROM  employees LIMIT 10,15;

 

#案例3:有奖金的员工信息,并且工资较高的前10名显示出来

SELECT 
    * 
FROM
    employees 
WHERE commission_pct IS NOT NULL 
ORDER BY salary DESC 
LIMIT 10 ;

 

 

 

 

经典案例测试:

# 1. 查询工资最低的员工信息: last_name, salary

#①查询最低的工资
SELECT MIN(salary)
FROM employees

#②查询last_name,salary,要求salary=SELECT last_name,salary
FROM employees
WHERE salary=(
    SELECT MIN(salary)
    FROM employees
);

# 2. 查询平均工资最低的部门信息

#方式一:
#①各部门的平均工资
SELECT AVG(salary),department_id
FROM employees
GROUP BY department_id
#②查询①结果上的最低平均工资
SELECT MIN(ag)
FROM (
    SELECT AVG(salary) ag,department_id
    FROM employees
    GROUP BY department_id
) ag_dep

#③查询哪个部门的平均工资=SELECT AVG(salary),department_id
FROM employees
GROUP BY department_id
HAVING AVG(salary)=(
    SELECT MIN(ag)
    FROM (
        SELECT AVG(salary) ag,department_id
        FROM employees
        GROUP BY department_id
    ) ag_dep

);

#④查询部门信息

SELECT d.*
FROM departments d
WHERE d.`department_id`=(
    SELECT department_id
    FROM employees
    GROUP BY department_id
    HAVING AVG(salary)=(
        SELECT MIN(ag)
        FROM (
            SELECT AVG(salary) ag,department_id
            FROM employees
            GROUP BY department_id
        ) ag_dep

    )

);

#方式二:
#①各部门的平均工资
SELECT AVG(salary),department_id
FROM employees
GROUP BY department_id

#②求出最低平均工资的部门编号
SELECT department_id
FROM employees
GROUP BY department_id
ORDER BY AVG(salary) 
LIMIT 1;

#③查询部门信息
SELECT *
FROM departments
WHERE department_id=(
    SELECT department_id
    FROM employees
    GROUP BY department_id
    ORDER BY AVG(salary) 
    LIMIT 1
);




# 3. 查询平均工资最低的部门信息和该部门的平均工资
#①各部门的平均工资
SELECT AVG(salary),department_id
FROM employees
GROUP BY department_id
#②求出最低平均工资的部门编号
SELECT AVG(salary),department_id
FROM employees
GROUP BY department_id
ORDER BY AVG(salary) 
LIMIT 1;
#③查询部门信息
SELECT d.*,ag
FROM departments d
JOIN (
    SELECT AVG(salary) ag,department_id
    FROM employees
    GROUP BY department_id
    ORDER BY AVG(salary) 
    LIMIT 1

) ag_dep
ON d.`department_id`=ag_dep.department_id;



# 4. 查询平均工资最高的 job 信息
#①查询最高的job的平均工资
SELECT AVG(salary),job_id
FROM employees
GROUP BY job_id
ORDER BY AVG(salary) DESC
LIMIT 1

#②查询job信息
SELECT * 
FROM jobs
WHERE job_id=(
    SELECT job_id
    FROM employees
    GROUP BY job_id
    ORDER BY AVG(salary) DESC
    LIMIT 1

);
# 5. 查询平均工资高于公司平均工资的部门有哪些?

#①查询平均工资
SELECT AVG(salary)
FROM employees

#②查询每个部门的平均工资
SELECT AVG(salary),department_id
FROM employees
GROUP BY department_id

#③筛选②结果集,满足平均工资>SELECT AVG(salary),department_id
FROM employees
GROUP BY department_id
HAVING AVG(salary)>(
    SELECT AVG(salary)
    FROM employees

);

# 6. 查询出公司中所有 manager 的详细信息.
#①查询所有manager的员工编号
SELECT DISTINCT manager_id
FROM employees

#②查询详细信息,满足employee_id=SELECT *
FROM employees
WHERE employee_id =ANY(
    SELECT DISTINCT manager_id
    FROM employees

);

# 7. 各个部门中 最高工资中最低的那个部门的 最低工资是多少

#①查询各部门的最高工资中最低的部门编号
SELECT department_id
FROM employees
GROUP BY department_id
ORDER BY MAX(salary)
LIMIT 1


#②查询①结果的那个部门的最低工资

SELECT MIN(salary) ,department_id
FROM employees
WHERE department_id=(
    SELECT department_id
    FROM employees
    GROUP BY department_id
    ORDER BY MAX(salary)
    LIMIT 1


);
# 8. 查询平均工资最高的部门的 manager 的详细信息: last_name, department_id, email, salary
#①查询平均工资最高的部门编号
SELECT 
    department_id 
FROM
    employees 
GROUP BY department_id 
ORDER BY AVG(salary) DESC 
LIMIT 1 

#②将employees和departments连接查询,筛选条件是①
    SELECT 
        last_name, d.department_id, email, salary 
    FROM
        employees e 
        INNER JOIN departments d 
            ON d.manager_id = e.employee_id 
    WHERE d.department_id = 
        (SELECT 
            department_id 
        FROM
            employees 
        GROUP BY department_id 
        ORDER BY AVG(salary) DESC 
        LIMIT 1) ;

 

posted on 2020-07-31 16:16  lfw123  阅读(196)  评论(0编辑  收藏  举报

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