求两个字符串的公共子串的最大长度
1 #include <iostream> 2 #include <string.h> 3 #include <algorithm> 4 using namespace std; 5 #define N 1100 6 7 char s[N]; 8 char t[N]; 9 10 int dp[N][N]; 11 12 int main() 13 { 14 cin >> s; 15 cin >> t; 16 int lens = strlen(s); 17 int lent = strlen(t); 18 int mx = 0; 19 for (int i = 0; i < lens; i++) { 20 for (int j = 0; j < lent; j++) { 21 if (s[i] == t[j]) { 22 if (i == 0 || j == 0) { 23 dp[i][j] = 1; 24 } else { 25 dp[i][j] = dp[i - 1][j - 1] + 1; 26 } 27 28 mx = max(mx, dp[i][j]); 29 } 30 } 31 } 32 33 cout << mx << endl; 34 return 0; 35 } 36 /* 37 abcde 38 bcd 39 */