LeetCode:Merge Sorted Array

Given two sorted integer arrays A and B, merge B into A as one sorted array.

Note:
You may assume that A has enough space (size that is greater or equal to m + n) to hold additional elements from B. The number of elements initialized in A and B are m and n respectively.

思路:从为了不覆盖未比较的元素,后往前比较数组A和B中元素的大小,并从后更新元素。

 

 1 class Solution {
 2 public:
 3     void merge(int A[], int m, int B[], int n) {
 4         int i=m-1,j=n-1,k=m+n-1;
 5         while(i>=0&&j>=0)
 6         {
 7             if(A[i]>B[j])
 8                 A[k--]=A[i--];
 9             else
10                 A[k--]=B[j--];
11         }
12         while(j>=0)
13             A[k--]=B[j--];
14     }
15 };

 

posted @ 2014-09-17 15:26  LeviCode  阅读(98)  评论(0编辑  收藏  举报