Leetcode 375. Guess Number Higher or Lower II

We are playing the Guess Game. The game is as follows:

 

I pick a number from 1 to n. You have to guess which number I picked.

Every time you guess wrong, I'll tell you whether the number I picked is higher or lower.

However, when you guess a particular number x, and you guess wrong, you pay $x. You win the game when you guess the number I picked.

Example:

n = 10, I pick 8.

First round:  You guess 5, I tell you that it's higher. You pay $5.
Second round: You guess 7, I tell you that it's higher. You pay $7.
Third round:  You guess 9, I tell you that it's lower. You pay $9.

Game over. 8 is the number I picked.

You end up paying $5 + $7 + $9 = $21.

Given a particular n ≥ 1, find out how much money you need to have to guarantee a win.

 1  def getMoneyAmount(self, n):
 2         """
 3         :type n: int
 4         :rtype: int
 5         """
 6         dp = [[0]*(n+1) for _ in range(n+1)]
 7         for gap in range(1,n):
 8             for lo in range(1, n+1-gap):
 9                 hi = lo + gap
10                 dp[lo][hi] = min(x + max(dp[lo][x-1], dp[x+1][hi]) for x in range(lo, hi))
11         return dp[1][n]   

 

posted @ 2016-12-23 15:10  lettuan  阅读(202)  评论(0编辑  收藏  举报