Leetcode 137. Single Number I/II/III

Given an array of integers, every element appears twice except for one. Find that single one.

本题利用XOR的特性， X^0 = X, X^X = 0, 并且XOR满足交换律。

 

 1 class Solution(object):
 2     def singleNumber(self, nums):
 3         """
 4         :type nums: List[int]
 5         :rtype: int
 6         """
 7         s = 0
 8         for x in nums:
 9             s= s^x
10         
11         return s

 

single number II/III可以用位操作。用Hash table也可以通过OJ

class Solution(object):
    def singleNumber(self, nums):
        """
        :type nums: List[int]
        :rtype: int
        """
        dict = {}
        for i in range(len(nums)):
            if nums[i] not in dict:
                dict[nums[i]] = 1
            else:
                dict[nums[i]] += 1
        
        for word in dict:
            if dict[word] == 1:
                return word

 

posted @ 2016-11-21 04:46  lettuan  阅读(124)  评论(0)  编辑  收藏  举报