【剑指offer】平衡二叉树

题目:输入一棵二叉树,判断该二叉树是否是平衡二叉树。

class Solution {
public:
    bool IsBalanced_Solution(TreeNode* pRoot) {
        if (pRoot == NULL) return true;
        return IsBalanced_Solution(pRoot->left) && IsBalanced_Solution(pRoot->right)&&(abs(getHeight(pRoot->left)-getHeight(pRoot->right))<=1);
    }
    int getHeight(TreeNode* root) {
        if (root == NULL) return 0;
        return max(getHeight(root->left), getHeight(root->right))+1;
    }
};

 

posted @ 2018-12-31 14:31  Little_Shel  阅读(99)  评论(0编辑  收藏  举报