网络流最小割(拆点)

题目链接:https://vjudge.net/contest/68128#problem/I

具体思路:网络流的最小割等于玩网络流的最大流量,注意拆点,以及拆点后边连的时候是拆点后第二个点连向目的地。

AC代码:

#include<stdio.h>
#include<string.h>
#include<algorithm>
#include<iostream>
using namespace std;
const int MAXN=100010;//点数的最大值
const int MAXM=400010;//边数的最大值
const int INF=0x3f3f3f3f;
struct Node
{
    int from,to,next;
    int cap;
} edge[MAXM];
int tol;
int head[MAXN];
int dep[MAXN];
int gap[MAXN];//gap[x]=y :说明残留网络中dep[i]==x的个数为y
int n;//n是总的点的个数,包括源点和汇点
void init()
{
    tol=0;
    memset(head,-1,sizeof(head));
}
void addadge(int u,int v,int w)
{
    edge[tol].from=u;
    edge[tol].to=v;
    edge[tol].cap=w;
    edge[tol].next=head[u];
    head[u]=tol++;
    edge[tol].from=v;
    edge[tol].to=u;
    edge[tol].cap=0;
    edge[tol].next=head[v];
    head[v]=tol++;
}
void BFS(int start,int end)
{
    memset(dep,-1,sizeof(dep));
    memset(gap,0,sizeof(gap));
    gap[0]=1;
    int que[MAXN];
    int front,rear;
    front=rear=0;
    dep[end]=0;
    que[rear++]=end;
    while(front!=rear)
    {
        int u=que[front++];
        if(front==MAXN)front=0;
        for(int i=head[u]; i!=-1; i=edge[i].next)
        {
            int v=edge[i].to;
            if(dep[v]!=-1)continue;
            que[rear++]=v;
            if(rear==MAXN)rear=0;
            dep[v]=dep[u]+1;
            ++gap[dep[v]];
        }
    }
}
int SAP(int start,int end)
{
    int res=0;
    BFS(start,end);
    int cur[MAXN];
    int S[MAXN];
    int top=0;
    memcpy(cur,head,sizeof(head));
    int u=start;
    int i;
    while(dep[start]<n)
    {
        if(u==end)
        {
            int temp=INF;
            int inser;
            for(i=0; i<top; i++)
                if(temp>edge[S[i]].cap)
                {
                    temp=edge[S[i]].cap;
                    inser=i;
                }
            for(i=0; i<top; i++)
            {
                edge[S[i]].cap-=temp;
                edge[S[i]^1].cap+=temp;
            }
            res+=temp;
            top=inser;
            u=edge[S[top]].from;
        }
        if(u!=end&&gap[dep[u]-1]==0)//出现断层,无增广路
            break;
        for(i=cur[u]; i!=-1; i=edge[i].next)
            if(edge[i].cap!=0&&dep[u]==dep[edge[i].to]+1)
                break;
        if(i!=-1)
        {
            cur[u]=i;
            S[top++]=i;
            u=edge[i].to;
        }
        else
        {
            int min=n;
            for(i=head[u]; i!=-1; i=edge[i].next)
            {
                if(edge[i].cap==0)continue;
                if(min>dep[edge[i].to])
                {
                    min=dep[edge[i].to];
                    cur[u]=i;
                }
            }
            --gap[dep[u]];
            dep[u]=min+1;
            ++gap[dep[u]];
            if(u!=start)u=edge[S[--top]].from;
        }
    }
    return res;
}
int main()
{
    int nn,m,temp;
    while(~scanf("%d%d",&nn,&m))
    {
        init();
        n=nn<<1;
        int s,t;
        scanf("%d%d",&s,&t);
        for(int i=1; i<=nn; i++)
        {
            scanf("%d",&temp);
            addadge(i,nn+i,temp);
        }
        int t1,t2;
        for(int i=1; i<=m; i++)
        {
            scanf("%d%d",&t1,&t2);
            addadge(t1+nn,t2,INF);
            addadge(t2+nn,t1,INF);
        }
        printf("%d\n",SAP(s,t+nn));
    }
    return 0;
}


 

posted @ 2018-10-28 17:30  Let_Life_Stop  阅读(373)  评论(0编辑  收藏  举报