记-ajax上传文件(js部分)

var formData = new FormData();

var postData1 = $("#domId1").val();

var postData2 = $("#domId2").val();

formData.append('postData1',postData1);

formData.append('postData2',postData2);

formData.append('postFile',$("#fileId")[0].files[0]);

$.ajax({

  url:接口url,

  type:"POST",

  dataType:"json",

  data:formData,

  processData: false,//不处理数据

  contentType: false,//不设置Content-type请求头

  success:function(result){

    pass;

  },

});

posted @ 2019-07-15 16:38  leon-chan  阅读(314)  评论(0编辑  收藏  举报