Leetcode:58. Length of Last Word
Description
Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
Example
Given s = "Hello World",
return 5.
思路
- 没啥好说的
代码
class Solution {
public:
int lengthOfLastWord(string s) {
int len = s.size();
if(len == 0) return 0;
int i = len - 1;
while(i >= 0 && s[i] == ' ')
i--;
int end = i;
while(i >= 0 && s[i] != ' ')
i--;
return end - i;
}
};