一道关于员工与部门查询的SQL笔试题

建表:

01 DEPARTMENTS:
02 DEPARTMENT_ID(primary key),
03 DEPARTMENT_NAME,
04 LOCATION
05  
06 EMPLOYEES:
07 EMPLOYEE_ID(primary key),
08 EMPLOYEE_NAME,
09 EMPLOYEE_JOB,
10 MANAGER,
11 SALARY,
12 DEPARTMENT_ID
    1. 列出EMPLOYEES表中各部门的部门号,最高工资,最低工资
1 select max(SALARY) as 最高工资,min(SALARY) as 最低工资,DEPARTMENT_ID from EMPLOYEES group by DEPARTMENT_ID;
    1. 列出EMPLOYEES表中各部门EMPLOYEE_JOB为'CLERK'的员工的最低工资,最高工资
1 select max(SALARY) as 最高工资,min(SALARY) as 最低工资,DEPARTMENT_ID as 部门号 from EMPLOYEES where EMPLOYEE_JOB = 'CLERK' group by DEPARTMENT_ID;
    1. 对于EMPLOYEES中最低工资小于1000的部门,列出EMPLOYEE_JOB为'CLERK'的员工的部门号,最低工资,最高工资
1 select max(SALARY) as 最高工资,min(SALARY) as 最低工资,DEPARTMENT_ID as 部门号 from EMPLOYEESas b
2 where EMPLOYEE_JOB ='CLERK' and 1000>(select min(SALARY) from EMPLOYEES as a where a.DEPARTMENT_ID = b.DEPARTMENT_ID) group by b.DEPARTMENT_ID
    1. 根据部门号由高而低,工资有低而高列出每个员工的姓名,部门号,工资
1 select DEPARTMENT_ID as 部门号,EMPLOYEE_NAME as 姓名,SALARY as 工资 from EMPLOYEES order by DEPARTMENT_ID desc,SALARY asc
    1. 写出对上题的另一解决方法
1 还没想到,如果你又答案,请联系www.nowamagic.net,我的联系方式在网站首页。
    1. 列出'张三'所在部门中每个员工的姓名与部门号
1 select EMPLOYEE_NAME,DEPARTMENT_ID from EMPLOYEES where DEPARTMENT_ID = (select DEPARTMENT_ID from EMPLOYEES where EMPLOYEE_NAME = '张三')
    1. 列出每个员工的姓名,工作,部门号,部门名
1 select EMPLOYEE_NAME,EMPLOYEE_JOB,EMPLOYEES.DEPARTMENT_ID,DEPARTMENTS.DEPARTMENT_NAME from EMPLOYEES,DEPARTMENTS where EMPLOYEES.DEPARTMENT_ID = DEPARTMENTS.DEPARTMENT_ID
    1. 列出EMPLOYEES中工作为'CLERK'的员工的姓名,工作,部门号,部门名
1 select EMPLOYEE_NAME,EMPLOYEE_JOB,DEPARTMENTS.DEPARTMENT_ID,DEPARTMENT_NAME from EMPLOYEES,DEPARTMENTS where DEPARTMENTS.DEPARTMENT_ID = EMPLOYEES.DEPARTMENT_ID andDEPARTMENT_JOB = 'CLERK'
    1. 对于EMPLOYEES中有管理者的员工,列出姓名,管理者姓名(管理者外键为MANAGER)
1 select a.EMPLOYEE_NAME as 姓名,b.EMPLOYEE_NAME as 管理者 from EMPLOYEES as a,EMPLOYEES as b where a.MANAGER is not null and a.MANAGER = b.EMPLOYEE_ID
    1. 对于DEPARTMENTS表中,列出所有部门名,部门号,同时列出各部门工作为'CLERK'的员工名与工作
1 select DEPARTMENT_NAME as 部门名,DEPARTMENTS.DEPARTMENT_ID as 部门号,EMPLOYEE_NAME as 员工名,EMPLOYEE_JOB as 工作 from DEPARTMENTS,EMPLOYEES
2 where DEPARTMENTS.DEPARTMENT_ID *= EMPLOYEES.DEPARTMENT_ID and EMPLOYEE_JOB = 'CLERK'
    1. 对于工资高于本部门平均水平的员工,列出部门号,姓名,工资,按部门号排序
1 select a.DEPARTMENT_ID as 部门号,a.EMPLOYEE_NAME as 姓名,a.SALARY as 工资 from EMPLOYEES as a
2 where a.SALARY>(select avg(SALARY) from EMPLOYEES as b where a.DEPARTMENT_ID = b.DEPARTMENT_ID) order by a.DEPARTMENT_ID
    1. 对于EMPLOYEES,列出各个部门中平均工资高于本部门平均水平的员工数和部门号,按部门号排序
1 select count(a.SALARY) as 员工数,a.DEPARTMENT_ID as 部门号 from EMPLOYEES as a
2 where a.SALARY>(select avg(SALARY) from EMPLOYEES as b where a.DEPARTMENT_ID = b.DEPARTMENT_ID) group by a.DEPARTMENT_ID order by a.DEPARTMENT_ID
    1. 对于EMPLOYEES中工资高于本部门平均水平,人数多与1人的,列出部门号,人数,按部门号排序
1 select count(a.EMPLOYEE_ID) as 员工数,a.DEPARTMENT_ID as 部门号,avg(SALARY) as 平均工资 from EMPLOYEES as a
2 where (select count(c.EMPLOYEE_ID) from EMPLOYEES as c where c.DEPARTMENT_ID = a.DEPARTMENT_ID and c.SALARY>(select avg(SALARY) from EMPLOYEES as b where c.DEPARTMENT_ID = b.DEPARTMENT_ID))>1
3 group by a.DEPARTMENT_ID order by a.DEPARTMENT_ID
    1. 对于EMPLOYEES中低于自己工资至少5人的员工,列出其部门号,姓名,工资,以及工资少于自己的人数
1 select a.DEPARTMENT_ID,a.EMPLOYEE_NAME,a.SALARY,(select count(b.EMPLOYEE_NAME) from EMPLOYEES as b where b.SALARY < a.SALARY) as 人数 from EMPLOYEES as a
2 where (select count(b.EMPLOYEE_NAME) from EMPLOYEES as b where b.SALARY<a.SALARY)>5

本文转自:http://www.nowamagic.net/database/db_EmployeeDepartmentSQL.php

 

posted @ 2013-11-27 23:04  LEITION  阅读(616)  评论(0编辑  收藏  举报