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折半查找比较次数

对n个记录的有序表作折半查找,则查找次数如下表。(通过表格下方的按钮和输入框可设置正整数n的值)

  查找成功 查找失败
至少比较 1  (int)log2(n+1)
至多比较 (int)(log2n)+1  (int)(log2n)+1

实现功能的代码如下:

<table border="0" cellspacing="1" cellpadding="2">
<tbody>
<tr>
<td style="border: 1px solid #448844;" align="center" valign="middle"><span style="font-size: 18px;">&nbsp;</span></td>
<td style="border: 1px solid #448844;" align="center" valign="middle"><span style="font-size: 18px;">查找成功</span></td>
<td style="border: 1px solid #448844;" align="center" valign="middle"><span style="font-size: 18px;">查找失败</span></td>
</tr>
<tr>
<td style="border: 1px solid #448844;" align="center" valign="middle"><span style="font-size: 18px;">至少比较</span></td>
<td style="border: 1px solid #448844;" align="center" valign="middle"><span style="font-size: 18px;">1</span></td>
<td style="border: 1px solid #448844;" align="center" valign="middle"><span id="a12" style="font-size: 18px;">&nbsp;(int)log<sub>2</sub>(n+1)</span></td>
</tr>
<tr>
<td style="border: 1px solid #448844;" align="center" valign="middle"><span style="font-size: 18px;">至多比较</span></td>
<td style="border: 1px solid #448844;" align="center" valign="middle"><span id="a21" style="font-size: 18px;">(int)(log<sub>2</sub>n)+1</span></td>
<td style="border: 1px solid #448844;" align="center" valign="middle"><span id="a22" style="font-size: 18px;">&nbsp;(int)(log<sub>2</sub>n)+1</span></td>
</tr>
</tbody>
</table>

<input type="button" value="-" onclick='
var n=parseInt(document.getElementById("nVal").value);
if(isNaN(n))
n=0;
n=(n>0?n-1:0);
document.getElementById("nVal").value=n;
document.getElementById("a12").innerHTML=Math.floor(Math.log(n+1)/Math.LN2);
document.getElementById("a21").innerHTML=document.getElementById("a22").innerHTML=Math.floor(Math.log(n)/Math.LN2)+1;
'>
<input type="number" id="nVal" style="width:120px" placeholder="设置正整数n" onkeyup='
var n=parseInt(this.value);
if(isNaN(n))
n=0;
document.getElementById("a12").innerHTML=Math.floor(Math.log(n+1)/Math.LN2);
document.getElementById("a21").innerHTML=document.getElementById("a22").innerHTML=Math.floor(Math.log(n)/Math.LN2)+1;
'>
<input type="button" value="+" onclick='
var n=parseInt(document.getElementById("nVal").value);
if(isNaN(n))
n=0;
++n;
document.getElementById("nVal").value=n;
document.getElementById("a12").innerHTML=Math.floor(Math.log(n+1)/Math.LN2);
document.getElementById("a21").innerHTML=document.getElementById("a22").innerHTML=Math.floor(Math.log(n)/Math.LN2)+1;
'>
View Code

 

posted on 2019-11-09 23:12  Leisureeen  阅读(5773)  评论(0编辑  收藏  举报

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