java 树形结构遍历

在Java中遍历树形结构可以使用深度优先算法(DFS)或广度优先算法(BFS)。

  1. 深度优先算法(DFS)的示例代码如下所示:

    class TreeNode {
        int val;
        List<TreeNode> children;
        
        public TreeNode(int val) {
            this.val = val;
            this.children = new ArrayList<>();
        }
    }
     
    public class Main {
        public static void main(String[] args) {
            // 创建一个树形结构
            TreeNode root = new TreeNode(1);
            
            TreeNode child1 = new TreeNode(2);
            TreeNode child2 = new TreeNode(3);
            TreeNode child3 = new TreeNode(4);
            
            root.children.add(child1);
            root.children.add(child2);
            root.children.add(child3);
            
            // 调用递归函数进行深度优先遍历
            dfsTraversal(root);
        }
        
        private static void dfsTraversal(TreeNode node) {
            if (node == null) return;
            
            System.out.println("当前节点值为:" + node.val);
            
            for (TreeNode child : node.children) {
                dfsTraversal(child);
            }
        }
    }

    输出结果将按照根节点、子节点等顺序打印每个节点的值。

    1. 广度优先算法(BFS)的示例代码如下所示:

      import java.util.*;
       
      class TreeNode {
          int val;
          List<TreeNode> children;
          
          public TreeNode(int val) {
              this.val = val;
              this.children = new ArrayList<>();
          }
      }
       
      public class Main {
          public static void main(String[] args) {
              // 创建一个树形结构
              TreeNode root = new TreeNode(1);
              
              TreeNode child1 = new TreeNode(2);
              TreeNode child2 = new TreeNode(3);
              TreeNode child3 = new TreeNode(4);
              
              root.children.add(child1);
              root.children.add(child2);
              root.children.add(child3);
              
              // 调用迭代函数进行广度优先遍历
              bfsTraversal(root);
          }
          
          private static void bfsTraversal(TreeNode node) {
              Queue<TreeNode> queue = new LinkedList<>();
              queue.offer(node);
              
              while (!queue.isEmpty()) {
                  TreeNode current = queue.poll();
                  
                  System.out.println("当前节点值为:" + current.val);
                  
                  for (TreeNode child : current.children) {
                      queue.offer(child);
                  }
              }
          }
      }

       

posted @ 2024-01-09 14:21  裸奔到月球  阅读(459)  评论(0编辑  收藏  举报