Java并发案例03---生产者消费者问题02

生产者消费者第二种情形


package com.maple.msb.one;


public class ProducerConsumer {
	public static void main(String[] args) {
		SyncStack ss = new SyncStack();
		Producer p = new Producer(ss);
		Consumer c = new Consumer(ss);
		new Thread(p).start();
		new Thread(p).start();
		new Thread(p).start();
		new Thread(c).start();
	}
}

class WoTou {
	int id; 
	WoTou(int id) {
		this.id = id;
	}
	public String toString() {
		return "WoTou : " + id;
	}
}

class SyncStack {
	int index = 0;
	WoTou[] arrWT = new WoTou[6];

	public synchronized void push(WoTou wt) {
		while(index == arrWT.length) {
			try {
				this.wait();
			} catch (InterruptedException e) {
				e.printStackTrace();
			}
		}
		this.notifyAll();		
		arrWT[index] = wt;
		index ++;
	}

	public synchronized WoTou pop() {
		while(index == 0) {
			try {
				this.wait();
			} catch (InterruptedException e) {
				e.printStackTrace();
			}
		}
		this.notifyAll();
		index--;
		return arrWT[index];
	}
}

class Producer implements Runnable {
	SyncStack ss = null;
	Producer(SyncStack ss) {
		this.ss = ss;
	}

	public void run() {
		for(int i=0; i<20; i++) {
			WoTou wt = new WoTou(i);
			ss.push(wt);
			System.out.println("生产了:" + wt);
			try {
				Thread.sleep((int)(Math.random() * 200));
			} catch (InterruptedException e) {
				e.printStackTrace();
			}			
		}
	}
}

class Consumer implements Runnable {
	SyncStack ss = null;
	Consumer(SyncStack ss) {
		this.ss = ss;
	}

	public void run() {
		for(int i=0; i<20; i++) {
			WoTou wt = ss.pop();
			System.out.println("消费了: " + wt);
			try {
				Thread.sleep((int)(Math.random() * 1000));
			} catch (InterruptedException e) {
				e.printStackTrace();
			}			
		}
	}
}
posted @ 2017-10-30 20:59  枫叶maple  阅读(133)  评论(0编辑  收藏  举报