HDU 1238 Substring
Substrings
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 10192 Accepted Submission(s): 4845
Problem Description
You are given a number of case-sensitive strings of alphabetic characters, find the largest string X, such that either X, or its inverse can be found as a substring of any of the given strings.
Input
The first line of the input file contains a single integer t (1 <= t <= 10), the number of test cases, followed by the input data for each test case. The first line of each test case contains a single integer n (1 <= n <= 100), the number of given strings, followed by n lines, each representing one string of minimum length 1 and maximum length 100. There is no extra white space before and after a string.
Output
There should be one line per test case containing the length of the largest string found.
Sample Input
2
3
ABCD
BCDFF
BRCD
2
rose
orchid
Sample Output
2
2
Author
Asia 2002, Tehran (Iran), Preliminary
Recommend
Eddy
#include <iostream>
#include <cstdio>
#include <cstring>
#include <string>
#include <algorithm>
#include <set>
#include <vector>
using namespace std;
string s[105];
vector<int>v;
bool cmp(string a,string b)
{
return a.length()<b.length();
}
int dfs(string &str,int n)
{
int len=str.length();
int flag=1;
for(int i=len;i>=1;i--){//倒序求最长子串
for(int j=0;i+j<=len;j++){
string temp=str.substr(j,i);
string t=temp;
string retemp=t.assign(t.rbegin(),t.rend());//赋以新值逆向迭代器
for(int k=1;k<n;k++){
if(s[k].find(temp)==-1&&s[k].find(retemp)==-1){
flag=0;
break;
}
}
if(flag)return temp.length();
flag=1;
}
}
return 0;
}
int main()
{
int t;
cin>>t;
while(t--)
{
int n;
cin>>n;
for(int i=0;i<n;i++)
{
cin>>s[i];
}
sort(s,s+n,cmp);
int ans = dfs(s[0],n);
cout<<ans<<endl;
}
return 0;
}