2.Add Two Numbers-两个单链表相加

You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.

Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 -> 8

 1 /**
 2  * Definition for singly-linked list.
 3  * public class ListNode {
 4  *     int val;
 5  *     ListNode next;
 6  *     ListNode(int x) { val = x; }
 7  * }
 8  */
 9 public class Solution {
10     public ListNode addTwoNumbers(ListNode l1, ListNode l2) {
11         ListNode c1 = l1;//定义两个指针变量 c1 c2
12         ListNode c2 = l2;
13         ListNode head = new ListNode(0);//定义一个新链表的头结点
14         ListNode d = head;//新链表的指针变量
15         int sum = 0;
16         while(c1 != null || c2 != null) {
17             if(c1 != null) {
18                 sum = sum + c1.val;
19                 c1 = c1.next;
20             }
21             if(c2 != null) {
22                 sum = sum + c2.val;
23                 c2 = c2.next;
24             }
25             d.next = new ListNode(sum%10);
26             d = d.next;
27             sum = sum /10;
28         }
29         if(sum == 1) {
30             d.next = new ListNode(1);
31         }
32         return head.next;
33         
34         
35     }
36 }

 

posted @ 2015-11-10 10:27  笨狗毒毒毒  阅读(220)  评论(0)  编辑  收藏  举报