高仿 django插拔式 及 settings配置文件

基于django中间件实现插拔式

start.py

from notify import *
send_all('好嗨哦')

settings.py

NOTIFY_LIST = [
    'notify.email.Email',
    'notify.msg.Msg',
    'notify.wechat.WeChat',
    'notify.qq.Qq',
]

notify __init__.py

import settings
import importlib

def send_all(content):
    for path in settings.NOTIFY_LIST:  # "notify.email.Email"
        module_path, cls_name = path.rsplit('.',maxsplit=1)  
        # module_path = 'notify.email'  cls_name = "Email"
        md = importlib.import_module(module_path)  # from notify import email
        cls = getattr(md,cls_name)  # 获取到文件中类的名字
        obj = cls()  # 实力化产生一个个类的对象
        obj.send(content)

notify email.py

class Email(object):
    def __init__(self):
        pass  # 发送邮件需要的前期准备

    def send(self,content):
        print('邮件通知:%s'%content)

仿django settings

目录结构

conf
  - settings.py
lib
  - conf
    - __init__.py
    - global_settings.py
start.py

start.py

import os
import sys

BASE_DIR = os.path.dirname(__file__)
sys.path.append(BASE_DIR)

if __name__ == '__main__':
    # os.environ.setdefault('xxx','conf.settings')
    os.environ['xxx'] = 'conf.settings'
    from lib.conf import settings
    print(settings.NAME)

lib conf __init__.py

import importlib
from lib.conf import global_settings
import os

class Settings(object):
    def __init__(self):
        for name in dir(global_settings):
            if name.isupper():
                setattr(self,name,getattr(global_settings,name))
        # 获取暴露给用户的配置文件字符串路径
        module_path = os.environ.get('xxx')
        md = importlib.import_module(module_path)  # md = settings
        for name in dir(md):
            if name.isupper():
                k = name
                v = getattr(md,name)
                setattr(self,k,v)

settings = Settings()

conf settings.py

NAME = '我是暴露给用户的自定义配置'
posted @ 2019-12-06 09:17  LD_Dragon_sky  阅读(228)  评论(0编辑  收藏  举报