spring3.2.2 remoting HTTP invoker 实现方式
最近跟朋友聊天，聊到他们现在项目的架构都是把数据层跟应用层分离开来，中间可以加memcached等的缓存系统，感觉挺好的，很大程度上的降低耦合，然后还明确分配了数据层跟应用层任务。也方便定位、找到问题。（我们都用最简单的架构，就没搞过分布式部署，小公司没办法o(︶︿︶)o），就找时间学习了，说不定以后就好应用上。这里用了 HTTP invoker方式，别的rmi或者jms等也大同小异。
这里我使用的是spring3.2.2，jar包就不列了，少哪个加哪个就可以了。
spring官方文档一共提供三种方式：通过Spring Web MVC，通过一个servlet指向跟不依赖web容器使用Sun's Java 6构建。我这里用的是第二种方式，别的官方文档讲解还是很清晰的，根据那个操作即可。
首先server端：
Model
model是需要序列化的才能remote传输
public class ServiceReso implements Serializable { private static final long serialVersionUID = 1L; private String id; private String serviceName; private String serviceAddress; public ServiceReso() { super(); } public ServiceReso(String id, String serviceName, String serviceAddress) { super(); this.id = id; this.serviceName = serviceName; this.serviceAddress = serviceAddress; } public final String getId() { return id; } public final void setId(String id) { this.id = id; } public final String getServiceName() { return serviceName; } public final void setServiceName(String serviceName) { this.serviceName = serviceName; } public final String getServiceAddress() { return serviceAddress; } public final void setServiceAddress(String serviceAddress) { this.serviceAddress = serviceAddress; } @Override public String toString() { return "{\"id\":\"" + this.id + "\",\"serviceName\":\"" + this.serviceName + "\",\"serviceAddress\":\"" + this.serviceAddress + "\"}"; } }
Dao
public interface ServiceResoDao { /** * 根据传入的id值返回ServiceReso对象 * * @param id * 需要查询的ServiceReso对象id * @return ServiceReso */ public ServiceReso find(String id); }
DaoImp
jdbc没有做持久化，采用了spring自带的JdbcTemplate，感觉还是挺好用的。
@Repository("serviceResoDao")
public class ServiceResoDaoImp implements ServiceResoDao {
@Autowired
private JdbcTemplate jdbcTemplate;
public ServiceReso find(String id) {
String sql = "select SERVERID,REALSERVERNAME,DSIPADDR from COSH_SERVICE_REGISTER where SERVERID=?";
ServiceReso serviceReso = jdbcTemplate.queryForObject(sql,
new Object[] { id }, new RowMapper<ServiceReso>() {
public ServiceReso mapRow(ResultSet rs, int rowNum)
throws SQLException {
ServiceReso serviceReso = new ServiceReso(rs
.getString("SERVERID"), rs
.getString("REALSERVERNAME"), rs
.getString("DSIPADDR"));
return serviceReso;
}
});
return serviceReso;
}
}
beans.xml:
这里的urlMapping是用来分发不同的请求，免得在servlet中对应每个bean。
<?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:context="http://www.springframework.org/schema/context" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd "> <context:component-scan base-package="com.blackbread" /> <bean class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer"> <property name="locations"> <value>classpath:jdbc.properties</value> </property> </bean> <bean id="springDSN" class="org.springframework.jdbc.datasource.DriverManagerDataSource"> <property name="driverClassName" value="${jdbc.driverClassName}"> </property> <property name="url" value="${jdbc.url}"></property> <property name="username" value="${jdbc.username}"></property> <property name="password" value="${jdbc.password}"></property> </bean> <bean id="jdbcTemplate" class="org.springframework.jdbc.core.JdbcTemplate" abstract="false" lazy-init="false" autowire="default"> <property name="dataSource"> <ref bean="springDSN" /> </property> </bean> <bean name="serviceResoDaoRemoting" class="org.springframework.remoting.httpinvoker.HttpInvokerServiceExporter"> <property name="service" ref="serviceResoDao" /> <property name="serviceInterface" value="com.blackbread.dao.ServiceResoDao" /> </bean> <bean name="urlMapping" class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping"> <property name="mappings"> <props> <prop key="/serviceResoDaoRemoting"> serviceResoDaoRemoting </prop> </props> </property> </bean> </beans>
web.xml
这里有个问题：servlet-mapping中的url-pattern如果不是这样写，而是改成/remoting/*之类的就会请求不到资源，望知道的兄弟告知下，不胜感激。
<?xml version="1.0" encoding="UTF-8"?> <web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"> <servlet> <servlet-name>dispatcherServlet</servlet-name> <servlet-class> org.springframework.web.servlet.DispatcherServlet </servlet-class> <init-param> <param-name>contextConfigLocation</param-name> <param-value>classpath*:beans.xml</param-value> </init-param> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>dispatcherServlet</servlet-name> <url-pattern>/*</url-pattern> </servlet-mapping> </web-app>
client端：
client需要将server端的接口类跟实体类打包成jar，加以引用。
service
public interface ServiceResoService { void getServiceReso(String id); }
serviceImp
@Controller("serviceResoService")
public class ServiceResoServiceImp implements ServiceResoService {
@Resource(name = "serviceResoDaoReomting")
ServiceResoDao serviceResoDao;
public void getServiceReso(String id) {
ServiceReso serviceReso;
try {
serviceReso = serviceResoDao.find(id);
System.out.println(serviceReso.toString());
} catch (RuntimeException e) {
System.out.println("未找到结果！");
}
}
}
beans.xml
<?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:context="http://www.springframework.org/schema/context" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd "> <context:component-scan base-package="com.blackbread" /> <bean id="serviceResoDaoReomting" class="org.springframework.remoting.httpinvoker.HttpInvokerProxyFactoryBean"> <property name="serviceUrl" value="http://localhost:8080/HttpInvokerDAO/serviceResoDaoRemoting" /> <property name="serviceInterface" value="com.blackbread.dao.ServiceResoDao" /> </bean> </beans>
web.xml
<?xml version="1.0" encoding="UTF-8"?> <web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"> <welcome-file-list> <welcome-file>index.jsp</welcome-file> </welcome-file-list> <listener> <listener-class> org.springframework.web.context.ContextLoaderListener </listener-class> </listener> <!-- 设置Spring容器加载配置文件路径 --> <context-param> <param-name>contextConfigLocation</param-name> <param-value>classpath*:beans.xml</param-value> </context-param> </web-app>
