清北最后冲刺 张浩威 吃鱼

为什么要考虑每个时刻呢，考虑每条鱼什么时候被吃不就行了吗，至于时刻相同编号大小的问题，用pair不就可以吗

#include <bits/stdc++.h>
using namespace std;
pair<int,int> a[200005],p;
int NOW,i,n,m,x,now;
int cmp(pair<int,int> i,pair<int,int> j) {return i.first>j.first || i.first==j.first && i.second>j.second;}
int main()
{
    freopen("fish.in","r",stdin);
    freopen("fish.out","w",stdout);
    while (cin>>m)
    {
        cin>>n>>x;
        NOW=0; now=0;
        for (i=1; i<=n; i++)
        {
            scanf("%d",&a[i].second);
            a[i].first=a[i].second;
            push_heap(a+1,a+i+1,cmp);
            if (i<=m) now++;
        }
        for (i=1; i<=m; i++)
        {
            if (!now) break;
            if (a[1].first>x) break;
            p = a[1];
            pop_heap(a+1,a+now+1,cmp);
            NOW++; now--;
            if (p.first<x && now+NOW<m)
            {
                now++;
                a[now]=p; a[now].first+=a[now].second;
                push_heap(a+1,a+now+1,cmp);
            }
        }
        cout<<m-now-NOW<<' '<<now<<endl;
    }
    return 0;
}