[剑指Offer] 7.斐波那契数列

 1 class Solution {
 2 public:
 3     int Fibonacci(int n) {
 4         int res[40] = {0};
 5         res[0] = 1;
 6         res[1] = 1;
 7         for(int i = 2;i < n;i ++){
 8             res[i] = res[i - 1] + res[i - 2];
 9         }
10         return res[n - 1];
11     }
12 };

 

posted @ 2017-02-24 03:16  Strawberry丶  阅读(131)  评论(0编辑  收藏  举报