摘要: 1 var 2 nnn,root,xx,nn,n,m,i,j:longint;ans:int64; 3 l,r,size,a,an,bn,am,bm:array[1..100000]of longint; 4 function new(x:longint):longint; 5 begin 6 inc(nn); 7 size[nn]:=1;a[nn]:=x; exit(nn); 8 end; 9 10 procedure insert(var t,x:longint); 11 begin 12 if t=0 then 13 begi... 阅读全文
posted @ 2013-03-18 17:26 lbz007 阅读(214) 评论(0) 推荐(0) 编辑
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