扔骰子

把一个骰子扔n次, n次朝上一面的点数和为s。

输入n, 打印出s的所有可能的值出现的概率。

from decimal import Decimal

def get_dice():
    # 一个骰子扔n次
    times = input('please input an integer\n')
    # 默认点数
    number = [1, 2, 3, 4, 5, 6]
    result = []
    dice = {}
    while times > 0:
        result.append(number)
        times -= 1

    length = len(result)
    # 所有可能性
    total = len(number) ** length

    if length >= 2:
        while length > 2:
            temp = []
            for i in result[-1]:
                for j in result[-2]:
                    temp.append(i+j)
            result.pop(-1)
            result[-1] = temp
            length -= 1

        for m in result[0]:
            for n in result[1]:
                dice[m+n] = dice.setdefault(m+n, 0) + 1
    else:
        for i in result[0]:
            dice[i] = 1

    for num, count in dice.iteritems():
        dice[num] = str(Decimal(100.0*count/total).quantize(Decimal('0.000'))) + '%'
    return dice

for k, v in get_dice().iteritems():
    print k, v