【Python3】操作文件，目录和路径
1.遍历文件夹和文件
Python代码
知识点：
1. os.walk 返回一个三元组，其中dirnames是所有文件夹名字,filenames是所有文件的名字,parent表示父目录。
2. case 1 演示如何遍历所有目录
3. case 2 演示如何遍历所有文件
4. os.path.join(dirname,filename):将"/test/java"和"helloworld.java"变成/test/java/helloworld.java
知识点：
1. shutil.copyfile：如何复制文件
2. os.path.exists: 如何判断文件夹是否存在
3. shutil.copytree: 如何复制目录树
3.分割路径和文件名
Python代码
知识点：
1. 这是哪个函数都返回二元组
2. case1 分隔目录和文件名
3. case2 分隔盘符和文件名
4. case3 分隔文件和扩展名
函数总结
引用
1. os.walk(spath)
2. os.path.split(spath)
3. os.path.splitdrive(spath)
4. os.path.splitext(spath)
5. os.path.join(path1,path2)
6. os.path.dirname(path)
7. os.path.exists(path)
8. shutil.copyfile(src, dst)
9. shutil.copytree(srcDir, dstDir)
4、文件备份程序
Python代码
Python代码
import os
import os.path
rootdir = "d:/test"
for parent,dirnames,filenames in os.walk(rootdir):
# case 1:
for dirname in dirnames:
print ( "parent is:" + parent)
print ( " dirnames is:" + dirname)
# case 2:
for filename in filenames:
print ( " parent is:" + parent)
print ( " filename with full path:" + os.path.join(parent,filename))
Python代码
import os
import os.path
rootdir = "d:/test"
for parent,dirnames,filenames in os.walk(rootdir):
# case 1:
for dirname in dirnames:
print ( "parent is:" + parent)
print ( " dirnames is:" + dirname)
# case 2:
for filename in filenames:
print ( " parent is:" + parent)
print ( " filename with full path:" + os.path.join(parent,filename))
知识点：
1. os.walk 返回一个三元组，其中dirnames是所有文件夹名字,filenames是所有文件的名字,parent表示父目录。
2. case 1 演示如何遍历所有目录
3. case 2 演示如何遍历所有文件
4. os.path.join(dirname,filename):将"/test/java"和"helloworld.java"变成/test/java/helloworld.java
2.复制文件
import shutil
import os
import os.path
src = "d:\\test\\test1.txt"
dst = "d:\\test\\test2.txt"
dst2 = "d:/test/test.txt"
dir1 = os.path.dirname(src)
print ("dir1 %s" %s dir1)
if(os.path.exists(src) == False):
os.makedirs(dir1)
f1 = open(src," w")
f1.write( "line a\n" )
f1.write( "line b\n" )
f1.close();
shutil.copy(src,dst)
shutil.copyfile(src,dst2)
f2 = open(dst," r ")
for line in f2:
print(line)
f2.close()
#测试复制文件夹树
try:
srcDir = "d:/test1"
dstDir = "d:/test2"
# 如果dstDir已经存在，那么shutil.copytree方法会报错
# 这也意味着你不能直接用d:作为目标路径
shutil.copytree(srcDir,dstDir)
except Exception as err:
print (err)
#Python代码
import shutil
import os
import os.path
src = "d:\\test\\test1.txt"
dst = "d:\\test\\test2.txt"
dst2 = "d:/test/test.txt"
dir1 = os.path.dirname(src)
print ("dir1 %s" %s dir1)
if(os.path.exists(src) == False):
os.makedirs(dir1)
f1 = open(src," w")
f1.write( "line a\n" )
f1.write( "line b\n" )
f1.close();
shutil.copy(src,dst)
shutil.copyfile(src,dst2)
f2 = open(dst," r ")
for line in f2:
print(line)
f2.close()
#测试复制文件夹树
try:
srcDir = "d:/test1"
dstDir = "d:/test2"
# 如果dstDir已经存在，那么shutil.copytree方法会报错
# 这也意味着你不能直接用d:作为目标路径
shutil.copytree(srcDir,dstDir)
except Exception as err:
print (err)
知识点：
1. shutil.copyfile：如何复制文件
2. os.path.exists: 如何判断文件夹是否存在
3. shutil.copytree: 如何复制目录树
3.分割路径和文件名
Python代码
import os.path
#常用函数有三种：分隔路径，找出文件名，找出盘符(window系统)，找出文件的扩展名。
spath = "d:/test/test.7z"
# case 1:
p,f = os.path.split(spath);
print ( "dir is:" + p)
print ( " file is:" + f)
# case 2:
drv,left = os.path.splitdrive(spath);
print ( " driver is:" + drv)
print ( " left is:" + left)
# case 3:
f,ext = os.path.splitext(spath);
print ( " f is: " + f)
print ( " ext is:" + ext)
Python代码
import os.path
#常用函数有三种：分隔路径，找出文件名，找出盘符(window系统)，找出文件的扩展名。
spath = "d:/test/test.7z"
# case 1:
p,f = os.path.split(spath);
print ( "dir is:" + p)
print ( " file is:" + f)
# case 2:
drv,left = os.path.splitdrive(spath);
print ( " driver is:" + drv)
print ( " left is:" + left)
# case 3:
f,ext = os.path.splitext(spath);
print ( " f is: " + f)
print ( " ext is:" + ext)
知识点：
1. 这是哪个函数都返回二元组
2. case1 分隔目录和文件名
3. case2 分隔盘符和文件名
4. case3 分隔文件和扩展名
函数总结
引用
1. os.walk(spath)
2. os.path.split(spath)
3. os.path.splitdrive(spath)
4. os.path.splitext(spath)
5. os.path.join(path1,path2)
6. os.path.dirname(path)
7. os.path.exists(path)
8. shutil.copyfile(src, dst)
9. shutil.copytree(srcDir, dstDir)
4、文件备份程序
Python代码
import os
import shutil
import datetime
'''''
作用：将目录备份到其他路径。
实际效果：
假设给定目录"/media/data/programmer/project/python" ，
备份路径"/home/diegoyun/backup/“ ，
则会将python目录备份到备份路径下，形如：
/home/diegoyun/backup/yyyymmddHHMMSS/python/xxx/yyy/zzz..
用法:更改这两个参数.
backdir:备份目的地.
copydirs:想要备份的文件夹.
'''
def mainLogic():
# add dirs you want to copy
backdir = " d:\\test "
print (backdir)
copydirs = []
copydirs.append( " d:\\temp " );
# copydirs.append("d:\\test");
print ( " Copying files =================== " )
start = datetime.datetime.now()
# gen a data folder for backup
backdir = os.path.join(backdir,start.strftime( " %Y-%m-%d " ))
# print("backdir is:"+backdir)
kc = 0
for d in copydirs:
kc = kc + copyFiles(d,backdir)
end = datetime.datetime.now()
print ( " Finished! =================== " )
print ( " Total files : " + str(kc) )
print ( " Elapsed time : " + str((end - start).seconds) + " seconds " )
def copyFiles(copydir,backdir):
prefix = getPathPrefix(copydir)
# print("prefix is:"+prefix )
i = 0
for dirpath,dirnames,filenames in os.walk(copydir):
for name in filenames:
oldpath = os.path.join(dirpath,name)
newpath = omitPrefix(dirpath,prefix)
print ( " backdir is: " + backdir )
newpath = os.path.join(backdir,newpath)
print ( " newpath is: " + newpath)
if os.path.exists(newpath) != True:
os.makedirs(newpath)
newpath = os.path.join(newpath,name)
print ( " From: " + oldpath + " to: " + newpath)
shutil.copyfile(oldpath,newpath)
i = i + 1
return i
def getPathPrefix(fullpath):
# Giving /media/data/programmer/project/ , get the prefix
# /media/data/programmer/
l = fullpath.split(os.path.sep)
# print(str(l[-1]=="")
if l[ - 1 ] == "" :
tmp = l[ - 2 ]
else :
tmp = l[ - 1 ]
return fullpath[0:len(fullpath) - len(tmp) - 1 ]
def omitPrefix(fullpath,prefix):
# Giving /media/data/programmer/project/python/tutotial/file/test.py ,
# and prefix is Giving /media/data/programmer/project/,
# return path as python/tutotial/file/test.py
return fullpath[len(prefix) + 1 :]
mainLogic()
