hdoj-1032-The 3n + 1 problem(坑题)
//巨坑的一道题,输入的m,n要判断大小,输出还要按照原来的顺序,范围还是i<=n<=j #include <iostream> #include <cstdio> #include <algorithm> using namespace std; int alro(int x) { int ct = 1; while (x != 1) { if (x & 1) x = 3*x+1; else x = x/2; ct++; } return ct; } int main() { int m,n; while (cin>>m>>n) { int sm = min(m ,n); int lar = max(m ,n); int maxn = 0; for (int i=sm; i<=lar; i++) { maxn = max(alro(i), maxn); } printf("%d %d %d\n", m, n, maxn); } return 0; }