hdoj-1285-确定比赛名次(拓扑排序)
1 /* 2 Name:hdoj-1285-确定比赛名次 3 Copyright: 4 Author: 5 Date: 2018/4/11 15:59:18 6 Description: 7 标准的拓扑排序模板题,注意要优先小号输出 8 */ 9 #include <iostream> 10 #include <queue> 11 #include <vector> 12 #include <cstring> 13 #include <algorithm> 14 using namespace std; 15 const int MAXN = 1e+5; 16 int du[MAXN], n , m, L[MAXN]; 17 vector<int> g[MAXN]; 18 int topsort() { 19 memset(du, 0, sizeof(du)); 20 for (int i=0; i<n; i++) { 21 for (int j=0; j<g[i].size(); j++) { 22 du[g[i][j]]++; 23 } 24 } 25 int tot = 0; 26 priority_queue<int, vector<int>, greater<int>> Q; 27 for (int i=0; i<n; i++) { 28 if (!du[i]) { 29 Q.push(i); 30 } 31 } 32 while (!Q.empty()) { 33 int x = Q.top(); 34 Q.pop(); 35 L[tot++] = x; 36 for (int j=0; j<g[x].size(); j++) { 37 int t = g[x][j]; 38 du[t]--; 39 if (!du[t]) { 40 Q.push(t); 41 } 42 } 43 } 44 if (tot == n) return 1; 45 return 0; 46 } 47 int main() 48 { 49 // freopen("in.txt", "r", stdin); 50 while (cin>>n>>m) { 51 memset(L, 0, sizeof(L)); 52 memset(g, 0, sizeof(g)); 53 for (int i=0; i<m; i++) { 54 int a, b; 55 cin>>a>>b; 56 a--; 57 b--; 58 if (find(g[a].begin(), g[a].end(), b) != g[a].end()) continue; 59 g[a].push_back(b); 60 } 61 if (topsort() == 1) { 62 cout<<L[0]+1 ; 63 for (int i=1; i<n; i++) { 64 cout<<" "<<L[i]+1; 65 } 66 } 67 cout<<endl; 68 } 69 return 0; 70 }