用Jersey构建RESTful服务1--HelloWorld
一、环境
1、Eclipse Juno R2
2. Tomcat 7
3. Jersey 2.7 下载地址( https://jersey.java.net/download.html)
二、流程
1.Eclipse 中创建一个 Dynamic Web Project ,本例为“RestDemo”
2.按个各人习惯建好包,本例为“com.waylau.rest.resources”
3.解压jaxrs-ri-2.7,
将api、ext、lib文件夹下的jar包都放到项目的lib下;
项目引入jar包
4.在resources包下建一个class“HelloResource”
- package com.waylau.rest.resources;
- import javax.ws.rs.GET;
- import javax.ws.rs.Path;
- import javax.ws.rs.Produces;
- import javax.ws.rs.PathParam;
- import javax.ws.rs.core.MediaType;
- @Path("/hello")
- public class HelloResource {
- @GET
- @Produces(MediaType.TEXT_PLAIN)
- public String sayHello() {
- return "Hello World!" ;
- }
- @GET
- @Path("/{param}")
- @Produces("text/plain;charset=UTF-8")
- public String sayHelloToUTF8(@PathParam("param") String username) {
- return "Hello " + username;
- }
- }
5.修改web.xml,添加基于Servlet-的部署
- <servlet>
- <servlet-name>Way REST Service</servlet-name>
- <servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class>
- <init-param>
- <param-name>jersey.config.server.provider.packages</param-name>
- <param-value>com.waylau.rest.resources</param-value>
- </init-param>
- <load-on-startup>1</load-on-startup>
- </servlet>
- <servlet-mapping>
- <servlet-name>Way REST Service</servlet-name>
- <url-pattern>/rest/*</url-pattern>
- </servlet-mapping>
6.项目部署到tomcat,运行
7.浏览器输入要访问的uri地址
http://localhost:8089/RestDemo/rest/hello
输出Hello World!
http://localhost:8089/RestDemo/rest/hello/Way你好吗
输出Hello Way你好吗
参考:https://jersey.java.net/documentation/latest/user-guide.html