[Golang] 初探之 sync.Once
Once 官方描述 Once is an object that will perform exactly one action,即 Once 是一个对象,它提供了保证某个动作只被执行一次功能,最典型的场景就是单例模式。
[Golang] 初探之 sync.Once
sync.Once 是 Golang package 中使方法只执行一次的对象实现,作用与 init 函数类似。但也有所不同。
- init 函数是在文件包首次被加载的时候执行,且只执行一次
- sync.Onc 是在代码运行中需要的时候执行,且只执行一次
当一个函数不希望程序在一开始的时候就被执行的时候,我们可以使用 sync.Once 。
例如:
package main import ( "fmt" "sync" ) func main() { var once sync.Once onceBody := func() { fmt.Println("Only once") } done := make(chan bool) for i := 0; i < 10; i++ { go func() { once.Do(onceBody) done <- true }() } for i := 0; i < 10; i++ { <-done } } # Output: Only once
sync.Once 使用变量 done 来记录函数的执行状态,使用 sync.Mutex 和 sync.atomic 来保证线程安全的读取 done 。
Once源码
// Copyright 2009 The Go Authors. All rights reserved. // Use of this source code is governed by a BSD-style // license that can be found in the LICENSE file. package sync import ( "sync/atomic" ) // Once is an object that will perform exactly one action. type Once struct { // done indicates whether the action has been performed. // It is first in the struct because it is used in the hot path. // The hot path is inlined at every call site. // Placing done first allows more compact instructions on some architectures (amd64/x86), // and fewer instructions (to calculate offset) on other architectures. done uint32 m Mutex } // Do calls the function f if and only if Do is being called for the // first time for this instance of Once. In other words, given // var once Once // if once.Do(f) is called multiple times, only the first call will invoke f, // even if f has a different value in each invocation. A new instance of // Once is required for each function to execute. // // Do is intended for initialization that must be run exactly once. Since f // is niladic, it may be necessary to use a function literal to capture the // arguments to a function to be invoked by Do: // config.once.Do(func() { config.init(filename) }) // // Because no call to Do returns until the one call to f returns, if f causes // Do to be called, it will deadlock. // // If f panics, Do considers it to have returned; future calls of Do return // without calling f. // func (o *Once) Do(f func()) { // Note: Here is an incorrect implementation of Do: // // if atomic.CompareAndSwapUint32(&o.done, 0, 1) { // f() // } // // Do guarantees that when it returns, f has finished. // This implementation would not implement that guarantee: // given two simultaneous calls, the winner of the cas would // call f, and the second would return immediately, without // waiting for the first's call to f to complete. // This is why the slow path falls back to a mutex, and why // the atomic.StoreUint32 must be delayed until after f returns. if atomic.LoadUint32(&o.done) == 0 { // Outlined slow-path to allow inlining of the fast-path. o.doSlow(f) } } func (o *Once) doSlow(f func()) { o.m.Lock() defer o.m.Unlock() if o.done == 0 { defer atomic.StoreUint32(&o.done, 1) f() } }
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