以闭包或函数为参数的函数

let storage = [1, 324, 64564, 125, 789, 91, 77, 12345]//创建测试库

func separate(orignArray: [Int], by filter: (Int) -> Bool) -> (paired: [Int], cantPaired: [Int]) {//分割数组的函数

    var paired: [Int] = []

    var cantPaired: [Int] = []

    for item in orignArray {

        if filter(item) {

            paired.append(item)

        }else {

            cantPaired.append(item)

        }

    }

    return (paired: paired, cantPaired: cantPaired)

}

 

func getOddNum(num: Int) -> Bool {//判断是否为奇数

    if num%2 != 0 {

        return true

    }else {

        return false

    }

}

 

func getEvenNum(num: Int) -> Bool {//判断是否为偶数

    if num%2 == 0 {

        return true

    }else {

        return false

    }

}

print("storage: \(storage)\n---------------------------------------------------")

print("getOdd:\n paired: \(separate(orignArray: storage, by: getOddNum).paired)\n cantPaired: \(separate(orignArray: storage, by: getOddNum).cantPaired)")

print("getEven:\n paired: \(separate(orignArray: storage, by: getEvenNum).paired)\n cantPaired: \(separate(orignArray: storage, by: getEvenNum).cantPaired)")


运行结果如下

storage: [1, 324, 64564, 125, 789, 91, 77, 12345]
---------------------------------------------------
getOdd:
 paired: [1, 125, 789, 91, 77, 12345]
 cantPaired: [324, 64564]
getEven:
 paired: [324, 64564]
 cantPaired: [1, 125, 789, 91, 77, 12345]

posted @ 2017-04-23 23:55  懒虫哥哥  阅读(130)  评论(0编辑  收藏  举报