摘要: 1 class Solution { 2 public: 3 bool isSymmetric(TreeNode *root) { 4 if (root == NULL) return true; 5 return dfs(root->left, root-... 阅读全文
posted @ 2014-04-01 16:05 卖程序的小歪 阅读(146) 评论(0) 推荐(0) 编辑